Skip to main content

All Questions

1 vote
1 answer
64 views

Evaluation of a telescoping sum

I have come to a problem in a book on elementary mathematics that I don't understand the solution to. The problem has two parts : a.) Factorize the expression $x^{4} + x^{2} + 1$ b.) Compute the ...
scipio's user avatar
  • 595
2 votes
5 answers
211 views

Finding sum of the series $\sum_{r=1}^{n}\frac{1}{(r)(r+d)(r+2d)(r+3d)}$

Find the sum: $$\sum_{r=1}^{n}\frac{1}{(r)(r+d)(r+2d)(r+3d)}$$ My method: I tried to split it into partial fractions like: $\dfrac{A}{r}, \dfrac{B}{r+d}$ etc. Using this method, we have 4 equations in ...
akhmeteni's user avatar
  • 671
1 vote
2 answers
98 views

If $S=\frac{1}{1+1^2+1^4}+\frac{2}{1+2^2+2^4}+\cdots+\frac{n}{1+n^2+n^4}$, then calculate $14S$.

If $$S=\frac{1}{1+1^2+1^4}+\frac{2}{1+2^2+2^4}+\cdots+\frac{n}{1+n^2+n^4}\,$$ find the value of $14S$. The question can be simplified to: Find $S=\sum\limits_{k=1}^n\,t_k$ if $t_n=\dfrac{n}{1+n^2+n^...
oshhh's user avatar
  • 2,642
2 votes
4 answers
748 views

Finding the infinite Sum of a series: $\sum\frac1{n(n+1)(n+2)}$ [duplicate]

Find the infinite Sum of the series with general term $\frac{1}{n(n+1)(n+2)}$. I decomposed the fraction upto this $1/(2n)-1/(n+1)+1/(2n+4)$. But I find no link about cancelling terms. So how should ...
Sohaib's user avatar
  • 51
5 votes
3 answers
201 views

Prove $\frac{1}{{4n^2 - 1}} = \frac{1}{{(2n + 1)(2n - 1)}} = \frac{1}{{2(2n - 1)}} - \frac{1}{{2(2n + 1)}}$

Could you explain the operation in the third step? $$\frac{1}{{4n^2 - 1}} = \frac{1}{{(2n + 1)(2n - 1)}} = \frac{1}{{2(2n - 1)}} - \frac{1}{{2(2n + 1)}}$$ It comes from the sumation $$\sum_{n=1}^\...
user avatar