Skip to main content

All Questions

1 vote
1 answer
89 views

How do I evaluate $\sum_{k=1}^nk^pr^k=?$

For this entire post, we have $r\ne1$, $n\in\mathbb N$. For the first half, $p\in\mathbb N$, and at the end $p\in\mathbb Q$. It is well known that $$\sum_{k=1}^nr^k=\frac{1-r^{n+1}}{1-r}$$ And $$\...
Simply Beautiful Art's user avatar
3 votes
2 answers
74 views

Finding Exact Values of Specific Infinite Series

Prove that $\Sigma_{n=1}^{\infty}(n/2^n)=2$ and that $\Sigma_{n=1}^{\infty}(n^2/2^n)=6$. Thoughts: I have a feeling that if someone shows me how to do one, I'll be able to figure out the other. So ...
user avatar
3 votes
6 answers
269 views

Is $\sum_{n=1}^{\infty} \frac{n-1}{n^2}$ convergent or divergent?

Is $\sum_{n=1}^{\infty} \frac{n-1}{n^2}$ convergent or divergent? I tried ratio test but didn't seem to work, and I also know that the limit goes to zero, but I can't say its convergence because then....
mamath's user avatar
  • 33
0 votes
2 answers
1k views

showing that the partial sums of $ \log(j) = n\log(n) - n + \text{O}(\log(n))$

I'm trying to show that the partial sums of $\log(j) = n\log(n) - n + \text{O}(\log(n))$ I know that $$\int_1^n\log(x)dx = n\log(n) - n + 1$$ so that this number is pretty close to what I want. Now ...
user296012's user avatar
4 votes
5 answers
338 views

Power series summation [closed]

Trying to find the sum of the following infinite series: $$ \displaystyle\sum_{n=1}^{\infty}\frac{{(-1)}^{n-1}}{(2n-1)3^{n-1}}$$ Any ideas on how to find this sum?
Ian Baker's user avatar
  • 277
0 votes
1 answer
70 views

How to calculate this sum?

Let $x_1,\cdots,x_k$ be numbers between 0 and 1. Then is it possible to get explicit expression for the following sum:$$\sum_{n_1,\cdots,n_k\geq 1} x_1^{n_1}\times C_{n_1+n_2}^{n_2}\times x_2^{n_2}\...
user111463's user avatar
1 vote
1 answer
78 views

Trying to understand a power series example from Advanced Calculus by Taylor

Example 2 from 21.1 in the book, Find an expansion in powers of $x$ of the function $$ f(x) = \int_{0}^{1} \frac{1-e^{-tx}}{t}dt $$ and use it to calculate $f(1/2)$ approximately. I ...
bryguy9312's user avatar
0 votes
2 answers
462 views

Proof for multiplication of two power series

Prove that $(\sum_{k=0}^\infty u^k)^2=\sum_{k=0}^\infty (k+1)u^k$ when |u|<1. This is a proof I need for a larger proof I was doing. I am stuck on this, so I was not able to make any notable ...
QmmmmLiu's user avatar
  • 211
4 votes
1 answer
4k views

Exponential series is cosh(x), how to show using summation?

I want to show that $$\cosh(x) = \sum_{n=0}^{\infty} ‎\frac{(x)^{2n}‎}{(2n)!}‎ $$ I know that $cosh(x) = \frac{exp(x)+exp(-x)}{2}$ but i cant seem to get there from the original series. I know that $$...
user135688's user avatar
0 votes
1 answer
2k views

By applying term-wise differentiation and integration find the sum of the series $\sum_{k=1}^{\infty}\frac{x^k}{k}$

I need to find the sum of the following series: $$\sum_{k=1}^{\infty}\frac{x^k}{k}$$ on the interval $x\in[a,b], -1<a<0<b<1$ using term-wise differentiation and integration. Can anyone ...
user avatar
0 votes
3 answers
165 views

Why $\sum_{n=0}^{\infty}(n+1)5^nx^n=\frac{1}{(1-5x)^2}$

Why $$\sum_{n=0}^{\infty}(n+1)5^nx^n=\frac{1}{(1-5x)^2}?$$ I know that $\sum_{n=0}^{\infty}x^n=\dfrac{1}{1-x}$, so by the same token, $\sum_{n=0}^{\infty}5^nx^n=\dfrac{1}{1-5x}$. Thus $$ \left(\...
Oria Gruber's user avatar
  • 12.8k

15 30 50 per page
1 2
3