All Questions
1
question
1
vote
1
answer
87
views
Why is Mergesort $O(n)$ rather than $O(n\log{n})$?
Assume we want a divide-and-conquer algorithm that finds the max and min of a set $S$ with $n = 2^k$ elements, e.g. mergesort. The recurrence for time complexity is
$T(n)=2*T(n/2) +2$, for $n>2$, ...