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3 votes
1 answer
244 views

How to find the function of a surface

Let’s say we have $f(x)=\sqrt{x}$ in range $\,x\in[0,5]\,$ and we revolved around the $x$-axis what would the function $z=z(x,y)$ of this new surface? How can I find this surface? I have the volume of ...
SirMrpirateroberts's user avatar
3 votes
2 answers
64 views

Is there a way to modify the solid of revolution integral to allow for solids of increasing and decreasing radius?

I am doing a project on tori as they relate to pool floaties and the volume of a normal torus can be calculated by the solids of revolution integral on a circle, Is there a way to modify the integral ...
Lachlan Mc's user avatar
2 votes
1 answer
275 views

On Surfaces of Revolution With Any Two Relations in $\Bbb R^2$ Such that One is the Axis (g) and the Other Revolves (f) defined by z=Rev[f(x),g(x)]:

For the last few years, I have tried a couple times to solve this problem that I came up with. Even though this may seem like a nonsensical idea, there is still a seed of wonder embedded into it. This ...
Тyma Gaidash's user avatar
1 vote
0 answers
73 views

Limits for the parameters of the parametric equation of a surface of revolution

According to Lipschutz's Differential Geometry book, A surface of revolution $S$ is obtained by revolving a plane curve $C$ (the profile curve) about a line $L$ (the axis of $S$) in its plane. If $x_{...
Invenietis's user avatar
1 vote
2 answers
150 views

Find the area of the surface formed by revolving the given curve about $(i)x$-axis and $(i)y$-axis

Q:Find the area of the surface formed by revolving the given curve about $(i)x-axis$ and $(i)y-axis$ $$x=a\cos\theta ,y=b\sin\theta,0\le\theta\le2\pi$$ About $x-$axis is, $S=2\pi\int_0^{2\pi}b\sin\...
raihan hossain's user avatar
2 votes
1 answer
2k views

Surface Area of Revolution around y=x

Consider the curve $x=-t^2$ , $y=\frac{t^3}{3}-t+1$ , $t\in[0,1]$. Find the surface area obtained by revolving the curve about the line $y=x$. On my textbook there are formulas to find the surface ...
arpf's user avatar
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