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2 votes
0 answers
88 views

Deriving the value of the series $\sum _{n=1}^{\infty }\left[\frac{2n}{e^{2\pi n}+1}+\frac{2n-1}{e^{\left(2n-1\right)\pi }-1}\right]$

I have been working on trying to show that $\displaystyle \sum _{n=1}^{\infty }\left[\frac{2n}{e^{2\pi n}+1}+\frac{2n-1}{e^{\left(2n-1\right)\pi }-1}\right]=\frac{\varpi ^2}{4\pi ^2}-\frac{1}{8}$ ...
Camishere 45's user avatar
1 vote
0 answers
67 views

Theorem requirements not satisfied but answer is correct?

In Ron Gordon's answer here, he uses the residue theorem to compute the sum $$\sum_{k=-\infty}^{\infty} \frac{(-1)^{k} (2 k-1)}{k^2-k+1}$$ The theorem for the case of infinite sums states that Let $f ...
Max0815's user avatar
  • 3,515
0 votes
1 answer
35 views

Termwise Differentiation of Convergent Series Involving the Riemann Zeta Function

Let $\zeta(s)$ be the Riemann zeta function. We know that $$\zeta(s) = \prod_p(1 - p^{-s})^{-1}, \ \operatorname{Re} s > 1$$ in the sense that the righthand side converges absolutely to $\zeta(s)$ ...
Johnny Apple's user avatar
  • 4,429
1 vote
0 answers
46 views

Construct a sequence of complex numbers $z_n$ such that $z_1=1$ and $S:=\displaystyle\sum_{n=1}^\infty z_n^k = 0$ for every $k \in \mathbb{N}$. [duplicate]

Construct a sequence of complex numbers $z_n$ such that $z_1=1$ and $S:=\displaystyle\sum_{n=1}^\infty z_n^k = 0$ for every $k \in \mathbb{N}$. I have some preliminary ideas. For now, fix $k=1$. Let $...
Grigor Hakobyan's user avatar
3 votes
1 answer
131 views

How to Prove Convergence of $\prod\limits_{n =1}^\infty \left(1-\frac{z^2}{n^2}\right)$ for any $z \in \mathbb{C}$?

For $\frac{\sin(\pi z)}{\pi z} =\prod\limits_{n =1}^\infty \left(1-\frac{z^2}{n^2}\right)$, prove convergence of $\prod\limits_{n =1}^\infty \left(1-\frac{z^2}{n^2}\right)$ for any $z \in \mathbb{C}$. ...
pie's user avatar
  • 6,620
0 votes
0 answers
31 views

Absolutely vs Non-Absolutely Convergent Infinite Product

Consider the following standard infinite product: $$ \prod_{n=1}^{+\infty} \left( 1 + \frac{(-1)^n}{2n-1}z \right) $$ This product is not absolutely convergent because: $$ \sum_{n=1}^{+\infty} \left|...
Matteo Menghini's user avatar
2 votes
0 answers
40 views

Cauchy product of absolutely convergent series

In Lang "Complex Analysis" (page 60) he gives a lengthy proof that if the power series $f= \sum a_n z^n, g = \sum b_n z^n$ both absolutely converge in some disc, then also their Cauchy ...
user1180027's user avatar
2 votes
0 answers
56 views

Can I substitute $\cos^{(k)}(0)+i\sin^{(k)}(0)$ for $i^k$ in a series with index k?

I was trying to come up with a derivation of Euler's Formula inspired by a section in Thomas' Calculus, and I am using the following equation in this derivation $$\sum_{k=0}^{\infty}\left(\frac{\cos^{(...
Matti Bock Guldager's user avatar
10 votes
2 answers
378 views

Associativity of infinite products

It is well-known that if $\sum_{n=1}^\infty a_n$ is an absolutely convergent complex series and $\mathbb N$ is partitioned as $J_1,J_2,\dots$, then the series $\sum_{j\in J_n}a_j$ for all $n$ and $\...
Hilbert Jr.'s user avatar
  • 1,434
0 votes
0 answers
30 views

Estimation of the absolute value of an infinite sum by its coefficient

I got this problem from a complex funtion, but it now has little to do with the complex analysis. $$\Theta(s)=\sum_{n=0}^{\infty}a_{2n}s^{2n}$$ I already have: $$c_1^n\frac{(\ln n)^{2n}}{(2n)!}\leq |...
Derek Xie's user avatar
1 vote
0 answers
33 views

maximal continuation of $\Pi_2(x)$

Consider the functions for $k\in \Bbb N$ $$ \Pi_k(x) := \sum_{n \in \Bbb N} e^{\frac{\log^k n}{\log x}} $$ $\Pi_1(x)$ converges for real $1/e<x<1$. $\Pi_1(x)$ is a Riemann zeta function i.e. $\...
zeta space's user avatar
0 votes
0 answers
32 views

Classifying a singularity (how to find limit)

I have $f(z) = \frac{e^{-z}sin(2(z-1)^2)}{(z^2-4)(z-1)^2}$ I already found that $z=2$ and $z=-2$ are poles of order $1$. To classify $z=1$ I am struggling. I wrote $f(z) = \frac{1}{(z-1)^2} \sum_{n=0}^...
adisnjo's user avatar
  • 247
0 votes
1 answer
27 views

Finding largest value $R$ for Laurent Series

Find the largest value $R$ such that the laurent series of $\frac{2}{z^2-1} + \frac{3}{2z-i}$ about $z=1$ converges for $0 < |z-1| < R$ I observed that the isolated singularities are at $z=1,-1,\...
adisnjo's user avatar
  • 247
0 votes
1 answer
39 views

Question about convergence of a sequence of functions from $\Gamma$ [closed]

Let $\rho(z) = \big|\frac{z-i}{z+i}\big|$. If $\begin{pmatrix} a & b \\ c & d \end{pmatrix} \in \operatorname{SL}_2(\mathbb{Z})$, then we have that $\left(\rho\left(\frac{ai+b}{ci+d}\right)\...
MathLearner's user avatar
  • 1,021
1 vote
2 answers
86 views

Manipulating a sum

I have the following sum: $$ S = \sum_{n=1}^{+\infty} \frac{\cos(n\pi)}{(n+1)^2}$$ I'm asked to solve it using the following result: Let $f(z)$ be a complex function with it's poles $z_{k} \not\in \...
Hamza Amine's user avatar

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