Skip to main content

All Questions

1 vote
1 answer
95 views

Fields of intermediate cardinality (2)

Assuming the existence of a cardinal $\aleph_0 <\mathfrak{m} < 2^{\aleph_0}$, does it follow that there is a subfield of $\mathbb{R}$ of cardinality $\mathfrak{m}$ containing no algebraic ...
2 votes
2 answers
178 views

Fields of intermediate cardinality

Assuming the existence of a cardinal $\aleph_0 <\mathfrak{m} < 2^{\aleph_0}$, does it follow that there is a subfield of $\mathbb{R}$ of cardinality $\mathfrak{m}$?
1 vote
2 answers
422 views

Real numbers for beginners

I am thinking about the Wikipedia (I understand disputed) article about “definable real numbers”. It begins to say that, A real number $a$ is first-order definable in the language of set theory, ...
4 votes
1 answer
2k views

Definable real numbers

Reading this Wikipedia page I found this definition: A real number $a$ is first-order definable in the language of set theory, without parameters, if there is a formula $\phi$ in the language ...

15 30 50 per page
1 2 3 4 5
6