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3 votes
1 answer
73 views

Whether the given function is one-one or onto or bijective?

Let $f:\mathbb{R}\to \mathbb{R}$ be such that $$f(x)=x^3+x^2+x+\{x\}$$ where $\{x\}$ denotes the fractional part of $x$. Whether $f$ is one-one or onto or both? For one-one, we need to show that if $f(...
PAMG's user avatar
  • 4,500
1 vote
2 answers
120 views

Show that a function is $f$ bijective if $f(f(f(2x+3)))=x$ for all real $x$

Let $ f : \mathbb{R} \to \mathbb{R} $ is a function such that $$ \forall x\in\mathbb{R} : f(f(f(2x+3)))=x $$ Show that $f$ is bijective. We have to show that $f$ is injective and surjective. How do we ...
Trifon's user avatar
  • 113
0 votes
1 answer
46 views

How can I study the changes of $f_k(x)=\frac{e^{kx}-1}{2e^x}$

Let $f_k(x)$ be a function defined on $\mathbb{R}$ by $$f_k(x)=\frac{e^{kx}-1}{2e^x}$$ Where $k$ is a real , How can I study according to the values of $k$ the changes of the changes of $f_k$ I ...
Mostafa dd's user avatar
-3 votes
1 answer
100 views

Is this an injection from $\mathbb{R}_+$ to $(0,1)$? [closed]

I am wondering if $f: \mathbb{R}_+ \rightarrow (0,1)$ is an injection if $f$ just moves the decimal point to the left of each number an equal amount of times as how far the decimal point is from the ...
Princess Mia's user avatar
  • 3,019
0 votes
1 answer
26 views

Is it possible for a function to be continuously derivable over its entire open domain except for a removable discontinuity?

For example, is there a function $f \in \mathcal{C}(\mathbb{R}) \cap \mathcal{C}^1(\mathbb{R} \setminus \{ 0 \})$ such that $$ \exists \lim_{x \to 0} f'(x) = \lim_{x \to 0} \lim_{y \to x} \frac{f(y)-f(...
Juan's user avatar
  • 33
2 votes
2 answers
59 views

Is there a 'simple' function that flips the order of positive numbers without making them negative?

If I want to flip the order of some numbers, I can just multiply them with -1. But is there a not too complicated way to do it such that the numbers remain positive? Here's my attempt to word the ...
proof-of-correctness's user avatar
7 votes
2 answers
551 views

Find all functions $f:\mathbb{R}\rightarrow\mathbb{R}$ where $f(xf(y)+f(x)+y)=xy+f(x)+f(y)$

Find all functions $f:\mathbb{R}\rightarrow\mathbb{R}$ for two real numbers $x$ and $y$ where $f(xf(y)+f(x)+y)=xy+f(x)+f(y)$ For $x=0$ and $y=-f(0)$ then $f(-f(0))=0$. So, there is a real root $r_0$ ...
Farshid Farhat's user avatar
0 votes
1 answer
30 views

Finding domain and range without equation

We are given that $f(x)$ has domain $x \geq -4$ and $f(x) < -1$. All numbers in $\mathbb{R}$. Now we want to find the domain of $3f(x+1)+4$. My solution is $x+1 \geq -4$ so new domain is $x \geq -5$...
Salazar_3854708's user avatar
0 votes
1 answer
109 views

Show that $f(rx)=(f(x))^r$ for all $r\in \mathbb{Q}$ if $f(x+y)=f(x).f(y)$ for all $x,y\in \mathbb{R}$

$f:\mathbb{R}\to \mathbb{R}$ be function satisfying $f(x+y)=f(x).f(y)$ for all $x,y\in \mathbb{R}$ and $lim_{x\to 0} f(x)=1$ then show that $f(rx)=(f(x))^r$ for all $r\in \mathbb{Q}$. Here is what I ...
Shivam M's user avatar
  • 322
0 votes
0 answers
124 views

Converse of Bolzano Weierstrass Theorem

Bolzano Weierstrass Theorem (for sequences) states that Every bounded sequence has a limit point. However the converse is not true i.e. there do exist unbounded sequence(s) having only one real limit ...
Raminder Singh's user avatar
6 votes
4 answers
1k views

Why is the range a larger set than the domain?

When we have a function $f: \mathbb{R} \to \mathbb{R}$, I can intuitively picture that and think that for every $x \in \mathbb{R}$, we can find a $y \in \mathbb{R}$ such that our function $f$ maps $x$ ...
nocomment's user avatar
  • 319
0 votes
0 answers
38 views

Finding Sequence of Polynomials Whose Existence is Guaranteed

I'm interested in knowing whether we can find a sequence of polynomials (thanks to Stone-Weierstras) that converges to the Weierstrass function on some random interval (for instance, [-2 , 2]. The ...
Federico's user avatar
0 votes
2 answers
74 views

Nowhere continuous functions $f: \mathbb{R} \to \mathbb{R}$ such that $f(f(x)) = (f(x))^2$

Are there any nowhere continuous functions $f: \mathbb{R} \to \mathbb{R}$ satisfying the identity $f(f(x)) = (f(x))^2$ $\forall x \in \mathbb{R}$?
Rick Does Math's user avatar
6 votes
2 answers
367 views

How to strengthen $ h \big( 2 h ( x ) \big) = h ( x ) + x $ to force $ h $ to be linear?

Let $ h : \mathbb R \to \mathbb R $ be an injective function such that $$ h \big( 2 h ( x ) \big) = h ( x ) + x $$ for all $ x \in \mathbb R $, and $ h ( 0 ) = 0 $. What would be an as mild as ...
Redundant Aunt's user avatar
0 votes
1 answer
41 views

What is the correct inverse function for $f(x) = x^2$. Question about terminology.

Is the inverse function $g_1(x)=\sqrt{x}$ or is it $g_2(x)=-\sqrt{x}$. With what terminology can we describe both of these functions?
VLC's user avatar
  • 2,527
2 votes
1 answer
171 views

Proving if a function is continuous and not one-one then it has many such points.

Let $g$ be a continuous function on an interval $A$ and let $F$ be the set of points where $g$ fails to be one-to-one; that is $$F = \{x \in A : f(x)=f(y) \text{ for some $y \neq x$ and $y \in A$} \}$...
shahrOZe's user avatar
  • 317
0 votes
3 answers
72 views

{$\frac{1}{x}$} , $0<x\leq1$ in terms of {$x$}, $x\geq 1$, {$x$} is fractional part of $x$

$f(x)$ $=$ {$\frac{1}{x}$}, $0<x\leq1$ where {$x$} denotes the fractional part of $x$. $g(x) =$ {$x$}, $x\geq 1$ I want an expression for $f(x)$ in terms of x and $g(x)$. My try- If $x\in \mathbb{Z}...
user avatar
3 votes
1 answer
81 views

Suppose $\sum_{n\ge 1} |a_n| = A<\infty.$ Under what conditions is $\sum_{n\ge 1} \epsilon_n a_n = [-A,A]$, for $\epsilon_n \in \{-1,1\}$?

Consider the space of sequences: $$ \mathcal{E} = \{\{\epsilon_n\}_{n= 1}^{\infty}: \epsilon_n = \pm 1\} $$ This can be considered a "random choice of sign" in the probabilistic context, for ...
Integrand's user avatar
  • 8,369
0 votes
3 answers
94 views

Is it true that there is a bijection $[0, 1) \to \mathbb{R}$?

Is there is a bijection from $[0,1)$ to $\mathbb{R}$? I thought of an instance, $$\frac{\sqrt{x(1-x)}}{x-1}.$$
Carl's user avatar
  • 127
0 votes
1 answer
42 views

Explain a confusing bound for the integral of a decreasing function.

I am reading a solution of an exercise. In the solution, it says the following: Consider $g(x,t):=\frac{x}{(1+tx^{2})t^{\alpha}}$, where $x\in (0,\infty)$, $t=1,2,3,\cdots$ and $\alpha>\frac{1}{2}$...
JacobsonRadical's user avatar
-2 votes
2 answers
50 views

Let $a$ be a real number such that $a > 0$. Show that the function $f : [a, +\infty) \to \mathbb R, f(x) = \tfrac{1}{x}$ is uniformly continuous.

Let $a$ be a real number such that $a > 0$. Show that the function $$f : [a, +\infty) \to \mathbb R, f(x) = \dfrac{1}{x}$$ is uniformly continuous.
nana's user avatar
  • 1
0 votes
1 answer
106 views

Suppose that for every $x$, $y$ such that $x$ is not equal to $y$ we have $|f(x) − f(y)| < |x − y|$

Let $a$ and $b$ two real numbers such that $a < b$ and $f : [a, b] \to [a, b]$. Suppose that for every $x$, $y$ such that $x$ is not equal to $y$ we have $|f(x) − f(y)| < |x − y|$. Show that ...
mera's user avatar
  • 27
3 votes
2 answers
86 views

If following actions allowed, Find $F(2002,2020,2200)?$

If following actions allowed,Find $F(2002,2020,2200)?$ $$ F(x+t,y+t,z+t)=t+F(x,y,z);$$ $$ F(xt,yt,zt)=tF(x,y,z);$$ $$ F(x,y,z)=F(y,x,z)=F(x,z,y)$$ where x,y,z,t are real numbers. My attempt: $F(0,0,0)...
BaSaBu's user avatar
  • 59
0 votes
2 answers
89 views

Is there a name for a real-valued function whose input is also real?

I'm trying to write a sentence about a function $f:\mathbb{R}\to \mathbb{R}$, and I want to refer to it as real valued or as a scalar function, or some similar term, but I want that term to also ...
Mark's user avatar
  • 1,361
9 votes
3 answers
153 views

How different can $f(g(x))$ and $g(f(x))$ be?

Given $f,g: \mathbb{R} \rightarrow \mathbb{R}$, how "different" can $f(g(x))$ and $g(f(x))$ be? By "how different" I mean: Given two real-valued functions $a,b$ do there exist two real-valued ...
Tanny Sieben's user avatar
  • 2,471
-1 votes
1 answer
132 views

Is a function $f(x)=\ln({x^2-1})$ even and symmetric

We have a function: $$ f(x)=\ln(x^2-1) $$ The function is symmetric because: $D_f=(-\infty,-1) \ \cup\ (1,\infty)$ I understand this as if we would multipy this by $-1$ we would get the same $D_f$ ...
VLC's user avatar
  • 2,527
2 votes
2 answers
208 views

Why is this function continuous on $\mathbb R$?

Let $f:\Bbb{R}\to\mathbb R$ be a function with $f(0) = 1$ and $f(x+y) \le f(x)f(y)$ for all $x, y \in \Bbb{R}$. Prove that if $f$ is continuous at $0$, then $f$ is continuous on $\Bbb{R}$? THOUGHTS: ...
BigDikEnergy's user avatar
1 vote
2 answers
231 views

Set of constant functions are uncountable.

Let $F=$ $\{$ $f: [0,1] \rightarrow \mathbb{R}$ $:$ $f$ is constant$ \} $. I must show that $F$ is uncountable. Note, that for any $f \in F$, and any $c\in \mathbb{R}$, I will denote the constant ...
user avatar
2 votes
0 answers
72 views

Proving integral of a continuous function is continuous

Let $U \subset \mathbb{R}^N$ be an open set, let $f : U \times [a, b] \to \mathbb{R}$ be a continuous function. Consider the function $$g(x):= \int_a^b f(x,y) \,dy$$ with $x \in U$. i) Prove ...
james black's user avatar
  • 1,913
2 votes
2 answers
461 views

Strictly increasing bounded function of class $C^1$

Let $f:\mathbb{R} \to \mathbb{R}$ be a strictly increasing bounded function of class $C^1$. Prove that there exists a sequence $\{x_n\}_n$ of real numbers such that $x_n\to\infty$ and $\lim_{n \to \...
james black's user avatar
  • 1,913

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