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0 votes
0 answers
146 views

How do we get the number of prime divisors?

We have a natural square-free number $n$ such that $2^5\cdot 3^6\cdot 5^4\equiv 0 \pmod {\tau(n)}$. Which is the maximum number of different primes that can divide $n$ ? $$$$ We have that $\tau(n)$ is ...
Mary Star's user avatar
  • 14k
3 votes
0 answers
92 views

Are there infinite many primes $\ p\ $ that cannot divide $\ 3^n+5^n+7^n\ $?

Let $\ M\ $ be the set of the prime numbers $\ p\ $ such that $\ p\nmid 3^n+5^n+7^n\ $ for every positive integer $\ n\ $ , in short the set of the prime numbers that cannot divide $\ 3^n+5^n+7^n\ $. ...
Peter's user avatar
  • 85.1k
-1 votes
2 answers
124 views

How to understand special prime factorization method

Normally when we want to find the Prime Factorization of a number, we will keep dividing that number by the smallest prime number (2), until it can't be divided then we move on to the next prime ...
Hoang Minh Quang FX15045's user avatar
1 vote
0 answers
116 views

How many positive divisors of 7560 are coprime to 15?

I'm trying to find the amount of positive divisors of $7560$ that are coprime to $15$. I do know how to find the total number of positive divisors a number has but I am not sure how finding those who ...
Bilal Sheikh's user avatar
0 votes
0 answers
30 views

Why for every range of N numbers, there are always approximately 0.392*N numbers which contains perfect squares as factors? [duplicate]

As to my current understanding, when simplifying radicands of roots what we are really doing is checking if this said number contains a perfect square number as a factor. Studying the distribution of ...
thecuriousironman's user avatar
-1 votes
2 answers
499 views

Let $n$ be a positive integer relatively prime with $10$. Prove that the digits of hundreds of $n^{20}$ is even. [closed]

Let $n$ be a positive integer relatively prime with $10$. Prove that the hundreds digit of $n^{20}$ is even. I know this has something to do with $\bmod 1000$, I'm just not sure how to write a proof ...
youalreadyknow's user avatar
-1 votes
2 answers
50 views

Prove that $a|p+1$ if and only if ${\frac{a}{p} = \frac{1}{n} + \frac{1}{m} }$ such that $n,m \in N$ and $p$ is prime [duplicate]

Let $p$ be a prime and let $n$ be a natural number such that $n \gt a$ . Prove that $a|p+1$ if and only if exists integers $n,m$ Such that ${\frac{a}{p} = \frac{1}{n} + \frac{1}{m}}$
FcMegira's user avatar
0 votes
1 answer
41 views

How many numbers between 1 and 1,000 (both inclusive) are divisible by at least one of the prime between 1 to 50? How can I find this? [closed]

I was trying to solve a compettive programming problem in which constraints are so high so I want to deduce a formula for it so that i could do it for other ranges as well.
Arun Jain's user avatar
8 votes
1 answer
635 views

How many integers are there that are not divisible by any prime larger than 20 and not divisible by the square of any prime?

I tackled the problem in the following way but i'm not sure if i'm correct. I need the count of the numbers that have in their prime factorization only primes p such that $p \lt 20$ and those ...
Andrés Felipe Vargas Fontecha's user avatar
1 vote
0 answers
181 views

Question about Zeta-distribution regarding divisibility by primes

For $s>1$ the Riemann Zeta-function is $$\zeta(s)=\sum_{n=1}^{\infty}n^{-s}$$ For a random variable $X$ with values in $\Bbb{N}$, its distribution is given by $$\Bbb{P}[X=n]=\frac{n^{-s}}{\zeta(s)...
B.Swan's user avatar
  • 2,469
0 votes
1 answer
196 views

Calculate all prime numbers $x$, where $x^{18} - 1$ is divisible by $28728$

Question: Calculate all prime numbers $x$, where $x^{18} - 1$ is divisible by $28728$ Apparently, the answer is all prime numbers except $2, 3, 7,$ and $19.$ I did some prime factorisation and found ...
Alexander B's user avatar
5 votes
1 answer
195 views

Find all $n$ such that $n/d(n) = p$, a prime, where $d(n)$ is the number of positive divisors of $n$

Let $d(n)$ denote the number of positive divisors of $n$. Find all $n$ such that $n/d(n) = p$, a prime. I tried this, but only I could get two solutions. I proceeded like this - Suppose $$n = p^r \...
user avatar
0 votes
1 answer
477 views

Find numbers with n-divisors in a given range

I'm trying to answer this question. Are there positive integers $\le200$ which have exactly 13 positive divisors? What about 14 divisors? If yes, write them. If no, explain why not. Because I'm ...
user avatar
1 vote
1 answer
102 views

Checking if the Product of n Integers is Divisible by Prime N

Given $n$ integers, $x_1, ... , x_n$, is there some well-known procedure or algorithm that checks if the product $x_1 * ... * x_n$ is divisible by some arbitrary prime $N$ using minimal space? Since ...
user537534's user avatar
3 votes
3 answers
185 views

Divisors of $\left(p^2+1\right)^2$ congruent to $1 \bmod p$, where $p$ is prime

Let $p>3$ be a prime number. How to prove that $\left(p^2+1\right)^2$ has no divisors congruent to $1 \bmod p$, except the trivial ones $1$, $p^2+1$, and $\left(p^2+1\right)^2$? When $p=3$, you ...
Ragnar23's user avatar

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