Skip to main content

All Questions

2 votes
0 answers
68 views

Largest possible prime factor for given $k$?

Let $k$ be a positive integer. What is the largest possible prime factor of a squarefree positive integer $\ n\ $ with $\ \omega(n)=k\ $ (That is, it has exactly $\ k\ $ prime factors) satisfying the ...
Peter's user avatar
  • 85.1k
5 votes
1 answer
161 views

Infinitely many primes with $2$ and $3$ generating the same set of residues

Prove that there are sets $S$ and $T$ of infinitely many primes such that: For every $p\in S$ there exists a positive integer $n$ such that $p\mid 2^{n} - 3$. For every $p \in T$ the remainders mod $...
DesmondMiles's user avatar
  • 2,823
0 votes
1 answer
81 views

Totient minimal value for semiprimes

I have two question concerning Euler Totient of semiprimes. First question : given $N=p_1 * p_2$ and $M=p_3*p_4$ where $p_1,p_2,p_3,p_4$ are prime numbers greater than 5; and $M>N$ this means that ...
Davinator's user avatar
1 vote
1 answer
396 views

Using Euler's Totient Function, how do I find all values n such that, $\varphi(𝑛)=14$

I just recently started working with Euler's Totient Function, and I came across the problem of solving for all possible integers $n$ such that $\varphi(n)=14$. I know there are similar questions with ...
Rodrigoss's user avatar
0 votes
3 answers
344 views

Euler's product formula in number theory

Is there intuitive proof of Euler's product formula in number theory (not searching for probabilistic proof) which is used to compute Euler's totient function?
1b3b's user avatar
  • 1,276
1 vote
0 answers
801 views

number of coprimes to a less than b

We know that number of coprimes less than a number can be found using euler function https://brilliant.org/wiki/eulers-totient-function/ But if there are two numbers p,q and we need to find number of ...
Manoharsinh Rana's user avatar
3 votes
1 answer
236 views

Factorization of large (60-digit) number

For my cryptography course, in context of RSA encryption, I was given a number $$N=189620700613125325959116839007395234454467716598457179234021$$ To calculate a private exponent in the encryption ...
Marc's user avatar
  • 1,218
7 votes
1 answer
117 views

On numbers with small $\varphi(n)/n$

Let $\Phi(n) = \varphi(n)/n = \prod_{p|n}(p-1)/p$ be the "normalized totient" of $n$. Some facts: $\Phi(p) = (p-1)/p < 1$ for prime numbers with $\lim_{p\rightarrow \infty}\Phi(p) = 1$ $\Phi(n) = ...
Hans-Peter Stricker's user avatar
8 votes
0 answers
182 views

Odd numbers with $\varphi(n)/n < 1/2$

The topic was also discussed in this MathOverflow question. From $\varphi(n)/n = \prod_{p|n}(1-1/p)$ (Euler's product formula) one concludes that even numbers $n$ must have $\varphi(n)/n \leq 1/2$ ...
Hans-Peter Stricker's user avatar
1 vote
1 answer
975 views

Given $\varphi (n)$ and $n$ for large values, can we know prime factors of $n$

If a number is product of two primes, then given its totient function, we can know its prime factors, but how do we do this in generic case? If the number could have more than two prime factors can ...
Alex K's user avatar
  • 13
3 votes
3 answers
251 views

On the equation $\varphi(n)=\left(\frac{1+\sqrt{1+8n}}{8}\right)\cdot\left(\operatorname{rad}(n)-\frac{1+\sqrt{1+8n}}{2}\right)$

An integer is said to be an even perfect number if satisifies $\sigma(n)=2n$, where $\sigma(n)$ is the sum of the positive divisors of $n$. The first few even perfect numbers are $6,28,496$ and $8128$....
user avatar
6 votes
0 answers
153 views

Estimation of the number of solutions for the equation $\sigma(\varphi(n))=\sigma(\operatorname{rad}(n))$

For integers $n\geq 1$ in this post we denote the square-free kernel as $$\operatorname{rad}(n)=\prod_{\substack{p\mid n\\p\text{ prime}}}p,$$ that is the product of distinct primes dividing an ...
user avatar
0 votes
1 answer
163 views

On prime-perfect numbers and the equation $\frac{\varphi(n)}{n}=\frac{\varphi(\operatorname{rad}(n))}{\operatorname{rad}(\sigma(n))}$

While I was exploring equations involving multiple compositions of number theoretic functions that satisfy the sequence of even perfect numbers, I wondered next question (below in the Appendix I add a ...
user avatar
0 votes
1 answer
195 views

Finishing the task to find the solutions of $\frac{1}{x}-\frac{1}{y}=\frac{1}{\varphi(xy)},$ where $\varphi(n)$ denotes the Euler's totient function

In this post I evoke a variant of the equations showed in section D28 A reciprocal diophantine equation from [1], using particular values of the Euler's totient function $\varphi(n)$. I ask it from a ...
user avatar
11 votes
7 answers
3k views

Only finitely many $n$ such that $\phi(n) = m$

Let $\phi(n)$ be Euler's totient function. How do I show that there are only finitely many such $n$ with $\phi(n) = m$, for each positive integer $m$? I've written $n$ as a product of primes; $n = ...
the man's user avatar
  • 2,482
0 votes
3 answers
167 views

About the solutions of $x^{\varphi(yz)}+y^{\varphi(xz)}=z^{\varphi(xy)}$, being $\varphi(n)$ the Euler's totient

In this post we denote the Euler's totient function as $\varphi(n)$ for integers $n\geq 1$. I wondered about the solutions of the equation $$x^{\varphi(yz)}+y^{\varphi(xz)}=z^{\varphi(xy)}\tag{1}$$ ...
user avatar
3 votes
2 answers
145 views

Euler's Totient Function: $\phi(n)\geq n\cdot 2^{-r}$.

My friend's teacher made a list with this problem: If $n$ has $r$ distinct prime factors, show that: $$\phi(n)\geq n\cdot 2^{-r}$$ I tried to help her, but I am not very good in number theory
Xandin's user avatar
  • 65
4 votes
2 answers
308 views

On questions involving the radical of an integer and different number theoretic functions: the Euler's totient function

We denote for an integer $n>1$ its square-free kernel as $$\operatorname{rad}(n)=\prod_{\substack{p\mid n\\p\text{ prime}}}p,$$ with the definition $\operatorname{rad}(1)=1$. You can see this ...
user avatar
2 votes
0 answers
55 views

On variations of Erdős squarefree conjecture: presentation and a question as a simple case

I'm inspired in the so-called Erdős squarefree conjecture, this section from Wikipedia, to state in this post a question, involving a different arithmetic function, that due its difficulty I feel as ...
user avatar
2 votes
1 answer
68 views

On miscellaneous questions about perfect numbers II

Let $\varphi(m)$ the Euler's totient function and $\sigma(m)$ the sum of divisors function. We also denote the product of primes dividing an integer $m>1$ as $\operatorname{rad}(m)$, that is the ...
user avatar
4 votes
1 answer
331 views

Markov triples that survive Euler's totient function

I'm inspired in a recent post of this MSE. We denote the Euler's totient function in this post as $$\varphi(n)=n\prod_{p\mid n}\left(1-\frac{1}{p}\right).$$ Suppose we have three positive integers $a,...
user avatar
2 votes
2 answers
152 views

The arithmetic function $\frac{\operatorname{rad}(2n)}{n+\varphi(n)+1}$ and a characterization of twin primes

We denote the Euler's totient function as $\varphi(n)$, and the radical of the integer $n> 1$ as $$\operatorname{rad}(n)=\prod_{\substack{p\mid n\\ p\text{ prime}}}p,$$ taking $\operatorname{rad}(1)...
user avatar
2 votes
1 answer
162 views

On even integers $n\geq 2$ satisfying $\varphi(n+1)\leq\frac{\varphi(n)+\varphi(n+2)}{2}$, where $\varphi(m)$ is the Euler's totient

This afternoon I am trying to get variations of sequences inspired from the inequality that defines the so-called strong primes, see the definition of this inequality in number theory from this ...
user avatar
3 votes
0 answers
53 views

An integer sequence defined from a variation of the Lucas–Lehmer primality test: the case of the Euler's totient function

I did a variation of the so-called Lucas–Lehmer primality test, I say this Wikipedia. I've used the Euler's totient function $$\varphi(n)=n\prod_{\substack{p\mid n\\ p\text{ prime}}}\left(1-\frac{1}{...
user avatar
2 votes
1 answer
105 views

Square-free integers in the sequence $\lambda+\prod_{k=1}^n(\varphi(k)+1)$, where $\lambda\neq 0$ is integer

While I was exploring the squares in the sequence defined for integers $n\geq 1$ $$\prod_{k=1}^n(\varphi(k)+1),\tag{1}$$ where $\varphi(m)$ denotes the Euler's totient function I wondered a different ...
user avatar
2 votes
3 answers
650 views

For which natural numbers are $\phi(n)=2$?

I found this exercise in Beachy and Blair: Abstract algebra: Find all natural numbers $n$ such that $\varphi(n)=2$, where $\varphi(n)$ means the totient function. My try: $\varphi(n)=2$ if $n=3,4,...
Vinyl_cape_jawa's user avatar
0 votes
0 answers
708 views

If $a\mid b$ then $\phi(a)\mid \phi(b)$ for $a,b\in\mathbb{N}$ [duplicate]

Hey I would like to show that $a\mid b\Rightarrow \varphi(a)\mid\varphi(b)\qquad a,b\in\mathbb{N}$ where $\varphi(n)$ is the the totient function. My try: Let $a,b\in\mathbb{N}$ and $a\mid b$. ...
Vinyl_cape_jawa's user avatar
1 vote
1 answer
823 views

How to find modulo using Euler theorem?

I don't know how that's possible using phi, the question starts with this one: a) Decompose 870 in prime factors and compute, ϕ(870) I know how to resolve this, first 870 = 2*3*5*29 and ϕ(870)= ...
Dan's user avatar
  • 31
3 votes
1 answer
64 views

About the divisors of totient numbers

Are there infinitely many integers that do not divide any totient number? My try: If $a|b$ then $\phi(a)|\phi(b)$, so the main question would be equivalent to asking wether there are infinitely many ...
user3141592's user avatar
  • 1,919
0 votes
1 answer
827 views

Euler's totient function and prime factorization

I want to prove the following: Let $n \in \mathbb{N}$. Then, if $$2\varphi(n) + 2 = n$$ holds, there exists an odd prime $p$ such that $n=2p$. My guess is that one can use the multiplicative ...
IronMan12's user avatar
  • 337
7 votes
1 answer
1k views

On factoring and integer given the value of its Euler's totient function.

In an entrance test for admission into an undergraduate course in mathematics the following question was asked. Consider the number $110179$ this number can be expressed as a product of two distinct ...
Love Everything's user avatar
0 votes
1 answer
85 views

Calculate Euler inverse function

Given $n$ find all values n such that: $\phi(n) = 26$. I've searched over the web and I've managed to find the lower and upper bounds for n, but i don't know how to go on from this point. I'll be ...
Philip L's user avatar
  • 489
1 vote
1 answer
151 views

Factorization of Euler totient function

We know that if $~n = p_{1}^{a_1} \cdots p_{s} ^ {a_s}~$ then $~\phi(n) = p_1^{a_1 - 1}(p_1 - 1)\cdots p_s^{a_s - 1} (p_s - 1)$. If $~q~$ is prime dividing $~\phi(n)~$ then there are two situations:...
Igor's user avatar
  • 2,183
3 votes
0 answers
68 views

Product of the Euler phi function [duplicate]

Prove the following statement: If $n, m\in\mathbb{Z} $ and $g=$gcd$(n, m) $ then is $$\varphi(m, n) =\frac{ \varphi(m) \varphi(n) g} {\varphi(g)}. $$ Hint: Prove the statement with induction above ...
MathCracky's user avatar
2 votes
2 answers
165 views

Use congruences to factor $n=87463$ (Fermat's Factorization?)

I'm studying for my number theory test tomorrow, and these are the last questions in my study guide. I think I understand Fermat's factorization, however, I can't tell how my professor wants us to ...
Jake's user avatar
  • 55
5 votes
2 answers
98 views

Given $k$, what is the largest number $n$, such that $\phi(n) \le k$

Let $k$ be a positive integer and $n$ be the largest number $n$ with the property $\phi(n) \le k$. Does such a number $n$ exist for every $k$ ? How can I determine the number $n$ ? Such a number $n$ ...
Peter's user avatar
  • 85.1k
3 votes
1 answer
248 views

Efficiently doing prime factorisation by hand

I have a yes/no question first (if 2 questions are allowed in 1 post). When doing prime factorisation for using the Euler totient function can you use a particular prime more than once. (i.e. $p_{1} ...
Gregory Peck's user avatar
  • 1,727
0 votes
2 answers
57 views

Prove RSA formula to be correct

How can I mathematically prove that if: n = pq then $\phi$(n) = n + 1 - (p + q) I could prove it ofcourse with an example, but I'm sure there must be a better way. Any help would be appreciated
ralphie91's user avatar