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7 votes
1 answer
191 views

Factorization and irreducibilty for $x^n-2x^m+1$ trinomials.

I have encountered a weird phenomenon while trying to solve a problem on Reddit. Here is the phenomenon. Let $a>b \in \mathbb{N}$ and $p_{(a,b)} = x^a - 2x^b + 1$ It seems that if $gcd(a,b,c,d) = 1,...
Vatsa Srinivas's user avatar
-1 votes
2 answers
71 views

Is a polynomial monotone when the first derivative has only imaginary roots? [closed]

I have a polynomial over a specific the range. The first derivative has only two imaginary roots and no real roots. The first derivative is positive in the lower bound and upper bound. Does that mean ...
sonia's user avatar
  • 9
5 votes
1 answer
113 views

Irreducible $p(x) \in \mathbb{Q}[X]$ with roots $r, s$ such that $rs = 1$.

If $p(x) \in \mathbb{Q}[X]$ is irreducible and has two roots $r,s$ such that $rs = 1$, then $p(x)$ is of even degree. I'm not sure how to solve this problem. My initial idea was to consider the field ...
huh's user avatar
  • 464
0 votes
2 answers
79 views

Number of real roots of $f(x) = (x^6) + 2(x^4) + (x^2) - 2(x) + 1$

The question is to find the number of real roots of the polynomial - $f(x) = (x^6) + 2(x^4) + (x^2) - 2(x) + 1$ I used the Descartes rule of signs. Using it, it is clear that there are maximum number ...
Physics_enthus's user avatar
1 vote
0 answers
41 views

Minimal polynomial of a complex number $z$ that is also an algebraic integer does not have $z$ as a repeated root [duplicate]

Let $z\in \mathbb{C}$ be an algebraic integer, and let $P\in \mathbb{Z}[X]$ be its minimal polynomial over $\mathbb{Z}$. Prove that $(X-z)^2 \nmid P(X)$. My attempt: My first idea was to prove that $P'...
alien2003's user avatar
  • 1,144
2 votes
1 answer
64 views

Is there a 3rd degree irreducible polynomial over Q[x], such that two of it's roots' (over C[x]) product equals the third root?

So we have a polynomial in the form: $ax^3+bx^2+cx+d$, where $a,b,c,d\in\mathbb{Q}$, $a\neq 0$. And this is irreducible over $\mathbb{Q}[x]$, but is of course reducible over $\mathbb{C}[x]$. We have ...
MikMi4r68's user avatar
0 votes
2 answers
169 views

Let $\alpha = 2\cos(\frac{2\pi}{7})$. What is the minimal polynomial of $\alpha$ over $\mathbb{Q}$?

Let $\alpha = 2\cos(\frac{2\pi}{7})$. What is the minimal polynomial of $\alpha$ over $\mathbb{Q}$? After a lot of calculation, I found a polynomial such that $\alpha $ is a root: $f(x) = x^6 + 2x^5 -...
irrational's user avatar
7 votes
3 answers
400 views

Reducing $ax^6-x^5+x^4+x^3-2x^2+1=0$ to a cubic equation using algebraic substitutions

Use algebraic substitutions and reduce the sextic equation to the cubic equation, where $a$ is a real number: $$ax^6-x^5+x^4+x^3-2x^2+1=0$$ My attempts. First, I tried to use the Rational root ...
user1094359's user avatar
7 votes
3 answers
362 views

A precalculus solution for $x^6 - 3 x^4 + 2 x^3 + 3 x^2 - 3 x + 1 =0$

Using algebra (precalculus) and suggest the solution method for the polynomial $$x^6 - 3 x^4 + 2 x^3 + 3 x^2 - 3 x + 1 =0$$ I'm solving problems on polynomials. I'm stuck here. My attempts. First, I ...
user1094359's user avatar
6 votes
4 answers
437 views

Solve in exact form: $x^6 - x^5 + 4 x^4 - 4 x^3 + 4 x^2 - x + 1=0$ ( WolframAlpha failed)

Solve the polynomial in closed form: $$x^6 - x^5 + 4 x^4 - 4 x^3 + 4 x^2 - x + 1=0$$ WolframAlpha obviously failed. I tried several ways: I tried the Rational Root Thereom, but there is no rational ...
user1094359's user avatar
1 vote
0 answers
40 views

Irreducibilty (reducibility) of a family of polynomials

Let $k\geq 3$ and $p\geq 1$ be integers. Set $f_{k,p}(x):=x^k-px^{k-1}-(p+1)x-1$. I need to prove for which parameters $k$ and $p$, this polynomial is irreducible (over $\mathbb{Z}$). For instance, $...
Jean's user avatar
  • 629
2 votes
1 answer
54 views

Equation with polynomial with integer coeficients.

Let $p>3$ be a prime number. Prove that there doesn't exist a pair of polynomials $(f,g)\in{\mathbb{Z}[X]\times\mathbb{Z}[X]}$ such that: $X^{2p}+pX^{p+1}-1=[(X+1)^p+p\cdot f(X)]\cdot[(X-1)^p+p\...
alien2003's user avatar
  • 1,144
0 votes
1 answer
123 views

Monic polynomial of degree 2 or 3 in arbitrary integral domain

Let $R$ be an integral domain and $f\in R[x]$ be a monic polynomial of degree $2$ or $3$. Let $K$ be the field of fractions of $R$. Are the following statements true? $f$ is irreducible in $K[x]$ $\...
Thrash's user avatar
  • 349
0 votes
0 answers
86 views

How can you find the roots of a polynomial if all the roots are imaginary?

I am trying to find the roots of a 4th-degree polynomial by hand which is actually coming from the derivative of the open-loop transfer function of a control system to find the breakaway points for ...
Tunguska's user avatar
  • 123
0 votes
1 answer
406 views

$F$ characteristic $0$ and $f(X) \in F[X]$ irreducible over $F$ imply $f(X)$ has distinct roots...why must $F$ be of characteristic $0$?

I have a question on this simple corollary from Abstract Algebra by Saracino: Corollary 24.11 If $F$ is of characteristic $0$ and $f(X) \in F[X]$ is irreducible over $F$, then $f(X)$ has distinct ...
Leonidas's user avatar
  • 1,054

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