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0 votes
1 answer
53 views

Prove that $f(x)$ is irreducible in $\mathbb{Z}$ with $f(b)$ a prime, $f(b-1) \neq 0$ and $\Re(\alpha_i) < b -1/2$

I need some help with a lemma I need to prove. First I will provide some background with previous lemmas that I already have been able to prove. Maybe these lemmas are needed to proof the last lemma ...
Lucius Aelius Seianus's user avatar
0 votes
0 answers
58 views

Missing and alternating coefficients of polynomials

I will start my question by providing some necessary context: Let $g(x) = c_lx^l + ... + a_1x + a$ be a polynomial of degree $l$. $g$ is said to have no missing coefficients if $c_i \neq 0$ for all $...
Lucius Aelius Seianus's user avatar
1 vote
0 answers
80 views

Reduce Polynomial Over Real Numbers

I was given the question $x^8 + 16$ and told to reduce it as much as able over the real numbers. Here is what I tried $x^8 + 16$ $(x^4+4)^2-8x^4$ $(x^4+4-2^{3/2}x^2)(x^4+4+2^{3/2}x^2)$ I can not ...
Dan Lupu's user avatar
  • 203
1 vote
3 answers
197 views

why is $x^6-x^5 + x^3 - x^2 + 1$ irreducible over $\mathbb{Z}[x]$?

Why is $x^6-x^5 + x^3 - x^2 + 1$ irreducible over $\mathbb{Z}[x]$? It clearly has no integer roots, and in fact no real roots. Every polynomial with real coefficients can be written as a product of ...
user33096's user avatar
  • 2,031
2 votes
2 answers
125 views

Can all the roots of $ax^5+bx^2+c=0$, with real coefficients and $a,c\neq0$, be real numbers?

Let $ax^5+bx^2+c=0$ and $a,c\neq 0$ and $a,b,c$ are real numbers. Can all the roots of this quintic equation be real numbers? I divided each side by $a$ and I got $$x^5+\frac bax^2+\frac ca=0$$ Using ...
user1094359's user avatar
9 votes
5 answers
395 views

Find the sum of $\sum_{i=1}^{5}x^5_i+\sum_{i=1}^{5}\frac{1}{x^5_i}$

Suppose $x^5+5x^3+1=0$ and $x_i$ denotes all the complex roots. Find the sum of $$\sum_{i=1}^{5}x^5_i+\sum_{i=1}^{5}\frac{1}{x^5_i}$$ This polynomial is irreducible over $\Bbb Q[x]$. I used Vieta's ...
user1094359's user avatar
2 votes
1 answer
64 views

Is there a 3rd degree irreducible polynomial over Q[x], such that two of it's roots' (over C[x]) product equals the third root?

So we have a polynomial in the form: $ax^3+bx^2+cx+d$, where $a,b,c,d\in\mathbb{Q}$, $a\neq 0$. And this is irreducible over $\mathbb{Q}[x]$, but is of course reducible over $\mathbb{C}[x]$. We have ...
MikMi4r68's user avatar
15 votes
3 answers
642 views

Under the which condition, factorisation of $a_1^n+a_2^n+\cdots+a_n^n-na_1a_2a_3...a_n ?$ is possible?

Under the which condition, factorisation of the polynomial $$a_1^n+a_2^n+\cdots+a_n^n-na_1a_2a_3...a_n ?$$ is possible? I know possible cases: $$a^2+b^2-2ab=(a-b)^2$$ and $$a^3+b^3+c^3-3abc=(a+b+c)(a^...
User's user avatar
  • 1,659
6 votes
2 answers
401 views

Find the real root of the almost symmetric polynomial $x^7+7x^5+14x^3+7x-1$

Find the real root of following almost symmetric polynomial by radicals $$p(x)=x^7+7x^5+14x^3+7x-1$$ Here are my attempts. The coefficients of $p(x)$ are : $1,7,14,7,-1$. I wanted to try possible ...
user1094359's user avatar
3 votes
1 answer
293 views

Why can't wolfram alpha solve this simple quintic?

So I found out that some transformations break wolfram alpha's ability to solve polynomials. The simplest case I could find is the polynomial $$2x^{5}+5x^{4}+5x^{2}+1=0$$ for which the solution is $$x=...
Baby Hearty Bear's user avatar
7 votes
3 answers
400 views

Reducing $ax^6-x^5+x^4+x^3-2x^2+1=0$ to a cubic equation using algebraic substitutions

Use algebraic substitutions and reduce the sextic equation to the cubic equation, where $a$ is a real number: $$ax^6-x^5+x^4+x^3-2x^2+1=0$$ My attempts. First, I tried to use the Rational root ...
user1094359's user avatar
-2 votes
2 answers
99 views

Show that the polynomial $P(x)=x^4-x^2-x+2$ has no real roots [closed]

Using clever algebra show that the polynomial $$P(x)=x^4-x^2-x+2$$ has no real roots. Obviously, we can not use the derivative. Using the general quartic formula is terrible. I tried $$(x^2+1)^2-3x^...
user1094359's user avatar
0 votes
1 answer
80 views

Reduce the degree and solve the polynomial equation $x^6+ax^4-2x^3+1=0$ by algebraic tricks

Reduce the degree of the polynomial and solve by algebraic tricks: $$x^6+ax^4-2x^3+1=0$$ where $a\in\mathbb R$. $a=0$ is obviously trivial. I tried all possible algebraic variations. $$\frac {P(x)}{x^...
user1094359's user avatar
3 votes
3 answers
174 views

Find the all real roots of the polynomial $x^6+3 x^5+3 x-1=0$ in closed form

Find the all real roots of the polynomial $$x^6+3 x^5+3 x-1=0$$ in exact form. WolframAlpha gives only numerical results. I've asked a few similar questions before. The source of the problem comes ...
user1094359's user avatar
2 votes
1 answer
116 views

Solve the polynomial $x^6+x^5+x^4-2x^3-x^2+1=0$ in exact form

Try to reduce the degree of the polynomial $$P(x)=x^6+x^5+x^4-2x^3-x^2+1$$ by algebraic ways and find the possible solution method to $P(x)=0$. The source of the problem comes from a non-english ...
user1094359's user avatar

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