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3 votes
2 answers
147 views

A conjecture about the sum of Faulhaber polynomials mod 2.

Context: In this question I asked about "Finding a polynomial function for alternating $m$ numbers of odds and even numbers in sequences" I noticed that all Faulhaber polynomials are ...
pie's user avatar
  • 6,620
8 votes
1 answer
169 views

Finding a polynomial function for alternating m numbers of odds and even numbers in sequences

Context: The function $(-1)^n$ alternates between $1,-1$ because $n$ alternates between odd and even, I was trying to find a function $f(n)$ that will give $m$ positives then $m$ negatives and so on ...
pie's user avatar
  • 6,620
19 votes
2 answers
766 views

Is the smallest root of a polynomial always complex if the coefficients is the sequence of prime numbers?

The smallest root of a polynomial is defined as the root which has the smallest absolute value. Consider the polynomial $a_0 + a_1 x + a_2 x^2 + \cdots + a_n x^n$. I observed that if $a_n$, is the ...
Nilotpal Sinha's user avatar
1 vote
1 answer
106 views

$f(x)$ has a factor $(x-r)$, if and only if $f(r) = 0$ - why can't $f(r)$ be a factor of $(x-r)$?

It is clear from the polynomial remainder theorem that $(x-r)$ is a factor of $f(x)$ if $f(r) = 0$ Is there no function $f(r)$ which is a factor of $(x-r)$? does this only happen when $f(r) = 0$? $f(x)...
General ASWalter's user avatar
2 votes
4 answers
531 views

Find the least prime $p$, such that for some positive integers $a$, $b$, $c$, $d$, $(ab + a - b)(bc + b - c)(cd + c - d)(da + d - a) = 2023^2p.$

Problem Find the least prime $p$, such that for some positive integers $a$, $b$, $c$, $d$, $(ab + a - b)(bc + b - c)(cd + c - d)(da + d - a) = 2023^2p.$ This problem is from the algebra round of a ...
JHumpdos's user avatar
  • 167
1 vote
1 answer
314 views

Find all integers $n$ such that $(n - 1)^2 + 3$ divides $n^3 + 2023$.

Problem: Find all integers $n$ such that $(n - 1)^2 + 3$ divides $n^3 + 2023$. My Work: $(n - 1)^2 + 3 = n^2 - 2n + 4$, which is always greater than 0 for all integers n. Therefore, if $n^2 - 2n + 4$ ...
JHumpdos's user avatar
  • 167
4 votes
2 answers
217 views

prove that $x^{20}+(1-x)^{20}-20$ is square free

Prove that $x^{20}+(1-x)^{20}-20$ is square free (i.e. has no repeated roots). Note that the claim holds iff $p'(x)$ is coprime to $p(x)$, where $p(x)=x^{20}+(1-x)^{20}-20$. $p'(x)= 20x^{19}-20(1-x)^{...
user33096's user avatar
  • 2,031
0 votes
1 answer
91 views

Is the polynomial $p^{2k+2} - 4p^{k+2} + 6p^{k+1} - 4p^k + 1$ a square for integers $k \neq 1$ and $k \equiv 1 \pmod 4$?

My initial question in the present post is pretty basic: Is the (integer) polynomial $$p^{2k+2} - 4p^{k+2} + 6p^{k+1} - 4p^k + 1$$ a square for integers $k \neq 1$ and $k \equiv 1 \pmod 4$, and ...
Jose Arnaldo Bebita Dris's user avatar
6 votes
8 answers
1k views

If $x^{19}+x^{17}+x^{13}+x^{11}+x^{7}+x^{5}+x^{3}$ is divided by $(x^2 +1)$, then find the remainder

If the polynomial $x^{19}+x^{17}+x^{13}+x^{11}+x^{7}+x^{5}+x^{3}$ is divided by $(x^ 2 +1)$, then the remainder is: How Do I solve this question without the tedious long division? Using remainder ...
Rishi Shekher's user avatar
5 votes
2 answers
217 views

Proving that $x(x^2-1)(x^2-10)=c$ cannot have five integer solutions for any real $c$

I found this question that caught my attention at MSE and I did a solution, but I suspect something is wrong with the solution. Original problem says: Prove that for any real values of $c$, the ...
lone student's user avatar
  • 14.8k
0 votes
1 answer
79 views

A problem in polynomials to show that $a_{n−1}$ and $a_n$ must be coprime [closed]

Let P(x) = $a_0x^n$ + · · · + $a_{n−1}x$ + $a_n$ be a polynomial with integer coefficients. Suppose the equation P(x) = 0 has n distinct integer roots which are pairwisely coprime. Then prove that $a_{...
Mathtome's user avatar
9 votes
1 answer
250 views

Find all $n$ which $7(n^2 + n + 1)$ is perfect $4^{th}$ power.

Find all positive integer $n$ , which $7(n^2 + n + 1)$ is perfect $4^{th}$ power. What I tried Let $7(n^2 + n + 1) = a^4$ $\to$ $ 7 | a$ and $a$ is odd. We then get $(n^2 + n + 1) = 343k^4$ ; $k \in \...
Oleg Farenskiy's user avatar
0 votes
0 answers
58 views

What is the correct notation and the correct solution?

My Question is, Which one is a correct notation and a correct solution? $$2x+2 \mod (x^2-x-2)=2x+2$$ Or, $$\text{RemainderPolynomial} [2x+2,x^2-x-2,x]=2x+2$$ If, both are correct why the remainder ...
user avatar
0 votes
3 answers
115 views

Find sum of all natural numbers $n $ such that $(n^2+n+1)^2$ divides $1+n+n^2+...+n^{2195}$. [closed]

Update Find sum of all $n \in \mathbb{N}$ such that $(n^2+n+1)^2$ divides $n^{2195}+n^{2194}+...+n^2+n+1$. I have no idea. Can anyone help? At least with a hint. Thanks for the help in advance. ...
lap lapan's user avatar
  • 2,238
1 vote
3 answers
63 views

Finding number of integral solutions to an equation.

Find the number of integral solutions to: $$x^2+y^2-6x-8y=0.$$ My attempt: The equation can be rewritten as: $$x^2+y^2-6x-8y+9+16=25,$$ basically adding 25 to both sides, or equivalently, $$(x-...
MNIShaurya's user avatar

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