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0 votes
2 answers
80 views

How can I handle$~\exp(\ln|x|)~$to solve 1st order linear DE?

RHS and LHS are same. $$\exp\left(\ln\left(x\right)\right)=\exp\left(\ln\left(x\right)\right)\tag{1}$$ Taking log. $$\ln\left(\exp\left(\ln\left(x\right)\right)\right)=\ln\left(\exp\left(\ln\left(x\...
electrical apprentice's user avatar
1 vote
2 answers
48 views

Find the range of $y$ in a DE

Consider the equation $$y' = y^2 - y - 2 = (y+1)(y-2).$$ If $y(10) = 0$, find the range of $y(t)$ for $t>10$. That is, find the best $A$ and $B$ such that $A<y(t)<B$ for $t>10$. From ...
singularity's user avatar
1 vote
1 answer
115 views

Can modulus function present in a particular solution

Particular solution of $2ye^{\tfrac{x}{y}}dx+\Big(y-2xe^{\tfrac{x}{y}}\Big)dy=0$, $x=0$ when $y=1$ Attempt Put $x=vy$ $$ \frac{dx}{dy}=\frac{x}{y}-\frac{1}{2e^{\tfrac{x}{y}}}\\ \frac{dx}{dy}=v+y\...
Sooraj S's user avatar
  • 7,674
2 votes
2 answers
129 views

Solution of $\frac{\mathrm{d}y}{\mathrm{d}x}=y\mathrm{e}^x$ given $x=0$, $y=\mathrm{e}$

$\dfrac{\mathrm{d}y}{\mathrm{d}x}=y\mathrm{e}^x$, $x=0$ and $y=\mathrm{e}$. Find the particular solution. Attempt 1 $$ \dfrac{\mathrm{d}y}{\mathrm{d}x}=y\mathrm{e}^x\implies\dfrac{\mathrm{d}y}{y}=\...
Sooraj S's user avatar
  • 7,674