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1 vote
2 answers
45 views

Is the resolvent of a local operator local?

Let $A$ denote a bounded linear operator on the Hilbert space $l^2(\mathbb{Z})$. We call $A$ a local operator if and only if there exists a $C \geq 0$ such that $\langle e_x | A | e_y \rangle = 0 $ if ...
Andreas132's user avatar
0 votes
1 answer
41 views

Basis of eigenfunctions and spectrum

I have a linear, closed and densely defined operator $A$ defined on a Hilbert space $H$. I prove that the point spectrum consists of discrete eigenvalues, and that the eigenfunctions of $A$ and of $A^*...
Judicaël Mohet's user avatar
1 vote
0 answers
28 views

On self-adjoint extensions and multiplicity of eigenvalues

I hope you can help me with the following question. Let $B$ be a densely defined closed symmetric operator on a infinite-dimensional separable complex Hilbert space $\mathcal{H}$ with deficiency ...
Mario Ruiz's user avatar
0 votes
0 answers
20 views

spectral theory of pseudo-differential operators of class $S^m$

I would be very grateful if you could give me the titles of books that deal with the spectral theory of pseudo-differential operators of class $S^m$ Thank you very much.
Fadil adil's user avatar
-2 votes
1 answer
117 views

Thus $MV - VM = V^2$. So the spectrum of $V^2$ is $\sigma(V^2) = (\sigma(V))^2=0$. Why??

I am curious if this statement holds (it doesn't make much sense to me, but it was written in solutions in this form): $\sigma(A)=0\implies\sigma(A^2)=(\sigma(A))^2=0.$ Can anybody explain to me why ...
user avatar
1 vote
0 answers
37 views

Spectrum of $T(\cdots , x_{-2}, x_{-1}, (x_{0}), x_{1}, x_{2},\cdots )=(\cdots ,x_{-2}, x_{-1}, 4x_{0}, (3x_{-1}), x_{0}, x_{1}, x_{2},\cdots )$

Find spectrum, eigenvalues and eigenvectors of operator $T:\ell^2(\mathbb{Z})\to \ell^2(\mathbb{Z})$, defined by $$T(\cdots , x_{-2}, x_{-1}, (x_{0}), x_{1}, x_{2},\cdots )=(\cdots ,x_{-2}, x_{-1}, ...
stboy's user avatar
  • 33
2 votes
0 answers
44 views

Proof that the hausdorff distance $d_H( \sigma (A), \sigma(B)) \le r(A-B)$ for commuting operators $A,B$

I am supposed to prove that for two bounded commuting operators $A, B$ on a banach space, the hausdorff distance of the spectra $d_H(\sigma(A),\sigma(B))$ is less than or equal to the spectral radius ...
Julius Himmel's user avatar
0 votes
1 answer
81 views

spectrum of translation operator

Let $\displaystyle A: c \rightarrow c, (Ax)(n) = \frac{x(n+2)}{n^2}$. The task is to find point spectrum, continuous spectrum, and residual spectrum of $A$ and of adjoint operator $A^*$. $c$ is Banach ...
GeoArt's user avatar
  • 139
2 votes
1 answer
56 views

Characterization of normal Fredholm Operators

I'm working on the following problem, but I'm getting stuck on the last part. Here is the problem: Let $T \in \mathcal{B}(H)$ be normal. Prove $T$ is Fredholm if and only if $0$ isn't a limit point ...
Isochron's user avatar
  • 1,399
2 votes
1 answer
92 views

About the spectrum family of the multiplication operator

Let $<,>$ be the inner product of $L^2(\mathbb{R})$. For a measurable function $F:\mathbb{R}^d\to\mathbb{R}$, we define a multiplication operator $M_F:L^2(\mathbb{R}^d)\to L^2(\mathbb{R}^d)$, ...
neconoco's user avatar
1 vote
0 answers
65 views

Does this integral operator between Banach spaces have a non-trivial kernel?

In a question which was recently asked, the goal was to (dis)prove that the set of functions which satisfy a certain equation is trivial. There is already a very neat solution there, but I came up ...
Stratos supports the strike's user avatar
1 vote
1 answer
69 views

Definition of closure of operator

Let $\mathcal{H}$ be a Hilbert space and $A:\mathrm{dom}(A)\to\mathcal{H}$ be an unbounded operator. I have seen the following definition of the closure in a lecture: $$\mathrm{dom}(\overline{A})=\{x\...
B.Hueber's user avatar
  • 2,876
2 votes
1 answer
75 views

Applying Spectral Mapping Theorem to determine if $f(T)$ is compact

Given a self-adjoint, compact operator $T$ and a continuous $f:\sigma(T)\to\mathbb{R}$, I'm trying to determine the conditions under which $f(T)$ is also compact. I know of the Spectral Mapping ...
mtcicero's user avatar
  • 529
2 votes
1 answer
44 views

Spectral Permanence Remark in Murphy's C*-algebras

In Murphy's $C^{*}$-algebras book, he states theorem $2.1.11$ which is that if $\mathfrak{B} \subset \mathfrak{A}$ are $C^{*}$-algebras with $\mathfrak{A}$ unital such that $1_{\mathfrak{A}} \in \...
Isochron's user avatar
  • 1,399
3 votes
1 answer
62 views

uniqueness of the inversion to Riemann-Stieltjes integral equation

I believe that if, for a Riemann-Stieltjes integral with $h(s)$ of bounded variation, $$ \int_0^1 s^\alpha dh(s) = 0 \qquad\text{for any }\alpha\in(\alpha_0,\alpha_1) , \tag{1}\label{eq1}$$ then $h$ ...
Martin Lanzendörfer's user avatar

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