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0 votes
0 answers
44 views

Commutators of unbounded operators on Hilbert spaces

Commutation seems to be a tricky business when it comes to unbounded operators, because of the domain questions. I have some trouble understanding the usual material about commutators of unbounded ...
Hugo's user avatar
  • 57
1 vote
1 answer
62 views

Basis of eigenfunction of nonself-adjoint operator

If $H$ is a separable Hilbert space, $A$ is a bounded nonself-adjoint operator, $\{\lambda_n\}_{n\in\mathbb{Z}}$ are the eigenvalues of $A$, and the corresponding eigenfunctions are $\{\psi_n\}_{n\in\...
zeng's user avatar
  • 169
1 vote
0 answers
28 views

On self-adjoint extensions and multiplicity of eigenvalues

I hope you can help me with the following question. Let $B$ be a densely defined closed symmetric operator on a infinite-dimensional separable complex Hilbert space $\mathcal{H}$ with deficiency ...
Mario Ruiz's user avatar
0 votes
0 answers
46 views

Asking for reference about self adjointness

Is there someone that knows and can share any reference about the compactness and the self-adjointness of the operator \begin{equation} \pmb{\sigma}\cdot L \end{equation} on $H^1(\mathbb{R}^{3},\...
Davide's user avatar
  • 545
2 votes
1 answer
42 views

On functions of a self-adjoint operator of the form $U^{-1} A U$

I found in Reed Simon that, since $\mathcal{F}$ (Fourier Transform) is unitary in $L^2(\mathbb{R}^n)$ and the self-adjoint operator (in a suitable domain) $-\Delta = H_{0}$ can be expressed as $H_{0} =...
Alessandro Tassoni's user avatar
0 votes
0 answers
24 views

Inequality for inverse of an unbounded self-adjoint operator

Given an unbounded self-adjoint operator $A$ on some Hilbert space $\mathcal{H}$, and $\mu$ a non zero real number: I want to show that \begin{equation} \lVert (\mathbf{A} + i\mu \mathbf{I})^{-1} \...
Alessandro Tassoni's user avatar
3 votes
1 answer
84 views

exponential of operators - Trotter product formula

Let $H$ be a self-adjoint operator, bounded from below, with spectrum consisting of isolated eigenvalues $E_n (E_0 < E_1 < ...)$ with finite multiplicities $d(n)$, and $Tr[exp(- \beta H)] < \...
b.omega's user avatar
  • 181
2 votes
1 answer
111 views

Weinstein's bound on eigenvalues of self-adjoint operators

Consider a complex, separable Hilbert space $H$ and a (densely defined) self-adjoint operator $A: \mathcal D(A)\to H$. Assume that $A$ admits an orthonormal basis of eigenvectors $(\varphi_n)_{n\in \...
Jakob's user avatar
  • 428
2 votes
2 answers
87 views

Operator norm of powers of bounded normal operators and self adjoint operators on Hilbert space

I saw this problem in Sheldon Axler's Measure,Integration and Real Analysis Ex. $10B$, problem $17$ and $18$. Let's just restrict to the self adjoint case. What I am trying to show is that $||T^{n}||=|...
Dovahkiin's user avatar
  • 1,285
3 votes
2 answers
64 views

If $P$ is a selfadjoint operator on a Hilbert space satisfying $P^4 = P$, is $P$ an orthogonal projection?

I’ve been trying to solve this problem to no avail. I have proved already that the spectrum is a subset of $\{0,1\}$ just like for orthogonal projections. I’ve also proved $\lVert P \rVert = 1$. ...
Neckverse Herdman's user avatar
1 vote
1 answer
94 views

Is the composition of positive, self-adjoint operators on a Hilbert space positive?

Let $A,B$ be self-adjoint, bounded, linear operators on a Hilbert space $H$ over $\mathbb{R}$ such that $\langle Ax,x\rangle\geq 0$ and $\langle Bx,x\rangle\geq 0$ for all $x\in H$. Does it also hold ...
Suim's user avatar
  • 11
0 votes
0 answers
91 views

Decomposition of normal operators into selfadjoint ones: $T=A+iB$

Assume we are given a densely defined and closed operator $T$ on a Hilbert space such that $D(T)\cap D(T^*)$ is dense. I am looking for sufficient conditions for $T+T^*$ to be selfadjoint as well as ...
Benjamin's user avatar
  • 789
1 vote
0 answers
78 views

If $A\in B(H)$ commutes with all self-adjoint operators, then $A=\lambda I$ for some $\lambda\in\mathbb{R}$

Let $H$ be a complex Hilbert space and $A\in B(H)$. Could anyone explain why the following assertion is true: if $A$ commutes with all self-adjoint operators, then $A=\lambda I$ for some $\lambda\in\...
OSCAR's user avatar
  • 573
0 votes
0 answers
27 views

Property of being Fredholm after applying the Helmholtz operator

Consider a bounded self-adjoint operator $L$ on $L^2(\mathbb{R})$. I want to study its essential spectrum, thus I need to determine when is $L-\lambda I$ Fredholm. Am I right with the statement $$ L-\...
Gateau au fromage's user avatar
3 votes
1 answer
182 views

Reed and Simon, Fourier Analysis and Self-Adjointness, second corollary to Theorem X.$25$: how to show that $D(A^2)$ is dense in $D(A)$ for its norm?

This question arose while trying to figure out the proof of the second corollary to Theorem X.$25$ in Reed and Simon's Fourier Analysis, Self-Adjointness, stated as follows: Theorem X.$25$: Let $A : ...
Bruno B's user avatar
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