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Questions tagged [natural-numbers]

For question about natural numbers $\Bbb N$, their properties and applications

2 votes
4 answers
143 views

$H(n)=\lfloor\dfrac{b}{n}\rfloor- \lfloor \dfrac{a}{n} \rfloor=$ (roughly) # odd pairs $o, o+2 \in [a,b]$ such that $n \mid o$ or $n \mid o+2$

I came up with the following formula and deleted that question so that I don't have two questions on the same formula. Conjecture. Let $a, b, n \in 2\Bbb{N} + 1$ be odd natural numbers. Then the ...
SeekingAMathGeekGirlfriend's user avatar
2 votes
1 answer
219 views

How to prove formula related to $2$-adic valuation / $2$-adic absolute value and binary expansion

I would like to prove the following formula, which I have verified for every positive integer $n \ge 1$ up to $n = 10000$: $$n - \sum_{k=0}^{\lfloor \log_2{n} \rfloor}\left(\left\lfloor\frac{2n-1+2^{...
Fabius Wiesner's user avatar
1 vote
4 answers
261 views

Prove that $\sqrt{\frac{n}{n+1}}\notin \mathbb{Q}$

I would like to show that $$\forall n\in\mathbb{N}^*, \quad \sqrt{\frac{n}{n+1}}\notin \mathbb{Q}$$ I'm interested in more ways of proofing this. My method : suppose that $\sqrt{\frac{n}{n+1}}\in ...
Educ's user avatar
  • 4,800
17 votes
2 answers
5k views

Why don't we use Presburger's arithmetic instead of Peano's arithmetic?

I was reading about quantifier elimination and discovered the Presburger Arithmetic, the article mentions two points about it: It is decidable, complete and consistent. It omits multiplication ...
Red Banana's user avatar
  • 24.2k
17 votes
2 answers
4k views

Is aleph-$0$ a natural number?

Would I be right in saying that $\aleph_0 \in \mathbb N$? Or would it be a wrong thing to do?
user avatar
14 votes
8 answers
2k views

Why can't we define arbitrarily large sets yet after defining these axioms? (Tao's Analysis I)

In Tao's Analysis I I am very confused why he says we do not have the rigor to define arbitrarily large sets after defining the below 2 axioms: Axiom 3.4 If $a$ is an object, then there exists a set $...
Princess Mia's user avatar
  • 3,019
14 votes
2 answers
315 views

Prove that $\left (\frac{a^2 + b^2 +c^2}{a+b+c} \right) ^ {(a+b+c)} > a^a b^b c^c$

Prove that $\left (\dfrac{a^2 + b^2 +c^2}{a+b+c} \right) ^ {(a+b+c)} > a^a b^b c^c$ if $a$, $b$ and $c$ are distinct natural numbers. Is it possible using induction?
jon jones's user avatar
  • 1,188
13 votes
1 answer
704 views

What's the next base-ten non-pandigital factorial number after 41!?

By pandigital number I mean a number for which each digit in a given base occurs at least once (some definitions that state each digit must occur exactly once), and since I looking for numbers that ...
Galen's user avatar
  • 1,876
10 votes
2 answers
639 views

A matrix w/integer eigenvalues and trigonometric identity

Any intuition and/or rigorous arguments on the proofs of the following statements would be appreciated: Let $n$ be a natural number. (a) Consider the following Toeplitz/circulant symmetric matrix: $...
DVD's user avatar
  • 1,157
7 votes
4 answers
12k views

Is it correct to say that the natural numbers are a proper subset of the integers?

Is it correct to say that the natural numbers are a proper subset of the integers? $\mathbb{N} \subset \mathbb{Z}$. Just want to be absolutely sure.
The Pointer's user avatar
  • 4,322
7 votes
5 answers
7k views

How can I expand mathematical induction to rational numbers?

I know mathematical induction can be used to prove that a statements is true for all natural numbers (or those belonging to a certain subset of N). However, it is pretty obvious, unless I'm terribly ...
Gepapado's user avatar
  • 171
6 votes
1 answer
347 views

Define a model for $\mathbb N$ without set theory

I've been looking around for a long time about how to found mathematics on a solid base. This led me to a long and painful journey of avoiding circular loops. It led me to do a bit of elementary ...
Patrick Da Silva's user avatar
5 votes
2 answers
473 views

How to show $n=1+\sum_{k=1}^{n}\left\lfloor{\log_2\frac{2n-1}{2k-1}}\right\rfloor$ for every natural number $n$.

While answering a question here I noticed that: $$n=1+\sum_{k=1}^{n}{\left\lfloor{\log_2\frac{2n-1}{2k-1}}\right\rfloor}$$ for every natural number $n$. I tried to demonstrate it using Legendre's ...
Fabius Wiesner's user avatar
5 votes
1 answer
618 views

Explicit bijection between $\mathbb N$ and $\mathbb N \times \mathbb N$ [duplicate]

We can consider the quadratic scheme above for a possible explicit bijection between $\mathbb N$ and $\mathbb N \times \mathbb N$. The part $\mathbb N \times \mathbb N \to \mathbb N$ is easy via $(m,...
Achilles's user avatar
  • 251
4 votes
3 answers
7k views

Proof that binomial coefficient is a natural number [duplicate]

Possible Duplicate: Proof that a Combination is an integer What is the proof that the binomial coefficient is a natural number? $$k\ge0,n\ge k \implies {n \choose k} \in N,$$ I guess it's a ...
Kornelije Petak's user avatar

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