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0 votes
0 answers
37 views

Can there be a Borel measurable bijection between $\mathbb{R}$ and $\mathbb{R}^2$ [closed]

I know a bijection exists between those sets, that it can be constructed quite explicitly and that it can't be continuous. I'm just not sure about the Borel measurability part.
Saurons_Appendix's user avatar
0 votes
0 answers
17 views

How to find a measurable, Lebesgue invariant bijection between the interval and the 3-dimensional sphere [closed]

From a book I was reading I have the following statement: "It is a general fact of measure theory that there is a bijection $f : [0, 1) → \mathbb{S}^2$ such that both $f$ and $f^{-1}$ take ...
Riel Blakcori's user avatar
1 vote
1 answer
70 views

Why does $C=\{x\in\mathbb{R}:\nu(\{x\})\neq0\}$ belong to $\mathscr{B}(\mathbb{R})$?

Let $\nu$ be a finite measure on $(\mathbb{R},\mathscr{B}(\mathbb{R}))$. Let $C=\{x\in\mathbb{R}:\nu(\{x\})\neq0\}$. I want to show that $\nu$ can be decomposed into the sum of a discrete meausre, a ...
Beerus's user avatar
  • 2,493
1 vote
1 answer
33 views

Compactly supported Borel measure $\mu$ on $\mathbb{R}^d$ [closed]

Definition : If $\mu$ is any Borel measure on $\mathbb{R}^d$ then its support is defined as $$\text{supp}(\mu):=\{x\in\mathbb{R}^d:\text{every open neighbourhood of }x\text{ has positive measure}\}. $$...
A. Bond's user avatar
  • 371
3 votes
0 answers
47 views

Is the Evaluation Map on Bounded Borel Measurable Functions Borel Measurable?

I am working with a set $I$, defined as the closed interval $[0,1]$, and a set $X$, which consists of all bounded Borel measurable functions defined on $[0,1]$. The uniform metric on $X$ is defined by:...
f yz's user avatar
  • 51
0 votes
0 answers
65 views

Borel $\sigma$-field and the product $\sigma$-field

I have a question about the proof of lemma 1.5 of the textbook Measure Theory, Probability, and Stochastic Processes by Le Gall. Lemma 1.5: Suppose that $E$ and $F$ are separable metric spaces, and ...
Shujun Tan's user avatar
2 votes
1 answer
32 views

Finding measurable subsets of any given value?

I'm not sure if the following is true, but I would hope it is with the regularity properties of $\mu$. Let $X$ be a locally compact Hausdorff space with $\mu$ a nonzero Radon measure on $X$. Then ...
Isochron's user avatar
  • 1,399
-1 votes
1 answer
23 views

Image of measurable sets under one to one (a.e) functions

I want to know about this question that is image of a measurable set under a one to one (almost everywhere) function, measurable? Consider the following: Let $(X, \mathcal{B}_X)$ and $(Y, \mathcal{B}...
Reza Yaghmaeian's user avatar
0 votes
0 answers
38 views

Let $\omega =\rho d\theta$ be a volue form of the circle $S^1$. Who are the diffeomorphisms of the circle that let $\omega$ invariant?

Consider the parametrization $\phi:]0,2\pi[\to S^1$ given by $\phi(\theta)=e^{i\theta}$. So the Lebesgue measure is given in local coordinates by the form $d\theta_z(\partial_z)=1$. I know that the ...
Gomes93's user avatar
  • 2,155
1 vote
0 answers
27 views

Measure on the $d$-dimensional torus

I am looking for references, measure-integration theory where the $d$-dimensional torus $\mathbb{T}^d$ is treared rigorously: borel $\sigma$-algebra, measure functions, measures on $(\mathbb{T}^d,\...
mathex's user avatar
  • 616
1 vote
1 answer
68 views

Existence of probability measures $P$ such that for any $x\in \Omega$ and closed set $x\not\in A$, the inequality $ 0<P(A^c)$ holds.

Suppose $(\Omega, \Sigma)$ is a measurable space such that $\Omega$ is a topological space and $\Sigma$ is a Borel $\sigma$-algebra on $\Omega$. For any such measurable spaces $(\Omega, \Sigma)$, does ...
Krasiff's user avatar
  • 77
3 votes
1 answer
97 views

Does there always exist a probability measure $P$ such that for any $x,y\in X$ there exist neighborhoods $x\in U,y\in V$ for which $0<P(U),P(V)$?

Consider a measurable space $(X, \Sigma)$ such that $X$ is a Hausdorff space and $\Sigma$ is a Borel $\sigma$-algebra on $X$. For any such measurable space $(X, \Sigma)$, does there exist a ...
Krasiff's user avatar
  • 77
3 votes
1 answer
112 views

When is measurability of a function $f$ equivalent to $f$ being almost everywhere the limit of measurable functions?

I have a suspicion that the following is true: $\def\AAA {\mathcal{A}} \def\BBB {\mathcal{B}} \def\NN {\mathbb{N}}$ Theorem: let $(X,\AAA,\mu)$ be a complete measure space, and $(Y,\BBB)$ a measurable ...
Sam's user avatar
  • 5,166
2 votes
0 answers
61 views

Prove that infinite union of $\mathcal{F_{i}}$ is not always $\sigma$-algebra

$\mathcal{F_{1}}$ is some sub-algebra and $\mathcal{F_{n+1}}$ is class of all sets that can be represented as a countable union or intersection of sets $\mathcal{F_{n}}$ Prove that $\bigcup_{n \in \...
Ryuk's user avatar
  • 21
3 votes
1 answer
46 views

Example of an infinite compact measurable space

Let $X$ be a nonempty set with a $\sigma$-algebra $\mathcal{A}$. The notion of $\sigma$-algebra strictly lies between Boolean algebras and complete Boolean algebras. Clearly, $\mathcal{A}$ is a ...
Dots_and_Arrows's user avatar

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