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1 vote
1 answer
95 views

Fourier transform of incomplete gamma function

Ultimately I am interested in the Fourier transform of $$ e^{-i\zeta}(-i\zeta)^{-2\epsilon}\Gamma(2\epsilon,-i\zeta) $$ in a series expansion around $\epsilon=0$, so to first order in $$ \lim_{\...
Tobias's user avatar
  • 133
0 votes
2 answers
195 views

what are the branch points and branches of $g(z)=(z+ \sqrt{z})^{1/3}$?

And what if we for example shifted one of the roots, eg $f(z)=(z+ \sqrt{z-3})^{1/3}$? I already asked a more extensive version of this question here Branch cut/ points for square roots inside cubic ...
Noam's user avatar
  • 67
0 votes
0 answers
92 views

Branch cut/ points for square roots inside cubic roots- incorrect branching by mathematica or my mistake?

There's a lot of great information here about understanding the branch cuts and branch points of functions of the form ( for example ) $(z^3+1)^{1/2}$, sums of simple roots and products thereof. ...
Noam's user avatar
  • 67
1 vote
1 answer
327 views

Closed form expression for an integral

Let $\psi_q(z)$ be the q-DiGamma function defined for a complex variable $z$ with $\Re(z)>0$ as $$\psi_q(z)=\frac{1}{\Gamma_q(z)}\frac{\partial}{\partial z} (\Gamma_q(z))$$ where $\Gamma_q(z)$ is ...
Max's user avatar
  • 910
4 votes
1 answer
145 views

Closed form expression for $\psi_{e^{\pi}}^{(3)}(1-i)$

Let $\psi_q(z)$ be the q-DiGamma function defined for a real variable $\Re(z)>0$ as $$\psi_q(z)=\frac{1}{\Gamma_q(z)}\frac{\partial}{\partial z} (\Gamma_q(z))$$ where $\Gamma_q(z)$ is the q-Gamma ...
Max's user avatar
  • 910
0 votes
1 answer
132 views

Closed form expression for $\psi_{e^{\pi}}^{(3)}(1)$

Let $\psi_q(x)$ be the q-DiGamma function defined for a real variable $x>0$ as $$\psi_q(x)=\frac{1}{\Gamma_q(x)}\frac{\partial}{\partial x} (\Gamma_q(x))$$ where $\Gamma_q(x)$ is the q-Gamma ...
Max's user avatar
  • 910
3 votes
0 answers
168 views

Elliptic integrals of complex argument and parameter

Mathematica has the annoying habit to provide solutions involving incomplete elliptic integrals of the first kind $E(z|m)$, second kind $F(z|m)$ and third kind $\Pi(...
CNS's user avatar
  • 69
3 votes
1 answer
388 views

Hermite polynomials for non-integer degree

I have solved an eigenvalue problem using Mathematica and the answer is in terms of Hermite polynomials. Now, for integer degrees $H_n(z)$, I can find a nice definition. However, in the solution to ...
user2978125's user avatar
3 votes
1 answer
112 views

Cauchy's theorem and mathematica disagree? Integral involving branch points.

Consider the following integral: $$\int_{-\infty}^{\infty} \frac{dx}{\sqrt{x^2-2i\epsilon x -1}(x^2+1)}$$ where $\epsilon$ is an infinitesimal positive number. In the complex $x$-plane, the integrand ...
Arturo don Juan's user avatar
1 vote
0 answers
83 views

Conditions on the coefficients that the roots of a polynomial be less that or equal to unity in absolute value

Consider the polynomial $$f(x)=p_0x^n+p_1x^{n-1}+...+p_{n-1}x+p_n,~p_i \in \mathbb C.$$ Particularly, in the case of absolute stability of a multi-step numerical method, how can we find out the ...
Riaz's user avatar
  • 2,184
6 votes
1 answer
219 views

Why do Mathematica and Wolfram|Alpha say $\Gamma(-\infty)=0$?

According to Mathematica and Wolfram|Alpha, $\lim_{x\to -\infty}\Gamma(x)$ is equal to zero. See e.g https://www.wolframalpha.com/input/?i=gamma+function (at the bottom of the page), or try ...
Etaoin Wu's user avatar
0 votes
1 answer
295 views

How can I evaluate this complex integral equation on Wolfram?

I need to evaluate the complex line integrals in the following equation: $$g(z)=\frac{\int_0^z\zeta^{-5/6}(\zeta-1)^{-1/2}d\zeta}{\int_0^1\zeta^{-5/6}(\zeta-1)^{-1/2}d\zeta}.$$ Can someone advise me ...
niran90's user avatar
  • 477
0 votes
0 answers
37 views

Error in Taylor series using Mathematica

How many terms should be used in taylor series expansion of the function f(z) = e^z around z = 0 for a specific value of z = 30 + 30 i to get an error of less than 0.05 using Mathematica? ...
user790624's user avatar
1 vote
1 answer
88 views

Proving $ \sum^{\infty}_{k=1}\frac{\textrm{sin}(\frac{k\pi}{2})\textrm{cos}(k\delta)}{k}=1/4({\pi}+gd(i\delta)+gd(-i\delta))$

In Mathematica, we can show that \begin{equation}\label{gd} \sum^{\infty}_{k=1}\frac{\textrm{sin}(\frac{k\pi}{2})\textrm{cos}(kx)}{k}=\frac{1}{4}\big({\pi}+\textrm{gd}(ix)+\textrm{gd}(-ix)\big), \end{...
Mtheorist's user avatar
  • 343
0 votes
0 answers
155 views

Can any Gaussian integral with complex limits be written as a (complex) error function?

Can the integral, $$I = \int^{-x}_{-\infty} e^{-at^2}\ \mathrm dt,\ a \in \mathbb{C},\ Re(a) > 0,$$ be written as an error function? I tried, by substitution, $$\int^{-x}_{-\infty} e^{-at^...
lcabo's user avatar
  • 13

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