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0 votes
1 answer
71 views

How do we know the dual pairing between Lp spaces is well defined? [closed]

Let $(\Omega, \mathcal{A}, \mu)$ be a measure space and let $X \in L^p(\Omega, \mathcal{A}, \mu)$ and $Y\in L^q(\Omega, \mathcal{A}, \mu)$. Then the dual pair betweent these spaces is defined as $\...
guest1's user avatar
  • 365
2 votes
1 answer
50 views

$L_p$ norm estimate of a sum

Let $R>0$, and $(B_k)_{k \in \Bbb{N}}$ a collection of disjoint balls of radius R and let $f$ be a measurable function on $\mathbb{R}^n$ of the form $$f = \sum_{k=1}^{\infty} a_k X_{B_k}$$ for ...
Marios Gretsas's user avatar
1 vote
1 answer
30 views

Given $f \in L^p_{\text{loc}}(\Omega) \setminus L^\infty(\Omega)$, does it follow that $A \cap S(f,K) \neq \emptyset$ for all $K > 0$?

Context. Throughout this post I will be dealing with the Lebesgue measure over $\mathbb R^n$. Moreover, I denote the measure of a measurable set $E \subset \mathbb R^n$ by $|E|$ and $\Omega \subset \...
xyz's user avatar
  • 1,141
2 votes
2 answers
88 views

Does convolution preserve local integrability in the sense that if $f \in L^p_{\text{loc}}$ and $g \in L^1$, then $f \ast g \in L^p_{\text{loc}}$?

Consider the Euclidian space $\mathbb R^n$, where $n \in \mathbb N$ is a fixed integer, equipped with the Lebesgue measure. Let $L^p_{\text{loc}}(\mathbb R^n)$($1 \leqslant p < \infty$) denote the ...
xyz's user avatar
  • 1,141
3 votes
1 answer
48 views

Equivalent characterisation of the space $L^p_{\operatorname{loc}}(\Omega)$, where $\Omega$ is a non-empty open subset of $\mathbb R^n$?

Consider the euclidian space $\mathbb R^n$, where $n \in \mathbb N$ is an arbitrary integer, equipped with the usual Lebesgue measure. Moreover, let $\Omega \subset \mathbb R^n$ denote an arbitrary ...
xyz's user avatar
  • 1,141
1 vote
0 answers
45 views

Applying the Lebesgue Dominated Convergence Theorem without explicitly building a sequence of functions.

Let $\Omega \subset \mathbb R^n$ denote an arbitrary non-empty open set. The classical formulation of the Lebesgue Dominated Convergence Theorem (LDCT, for short) is as follows. LDCT. Let $(f_n)_{n \...
Temirbek Alikhadzhiyev's user avatar
2 votes
1 answer
122 views

How pathological are the $L^{p}$ functions?

The motivation for my question is simple: for Riemann integrable functions, we had, at worst, almost everywhere continuity. It's not that bad behavior wise, but it is integration wise. So we come up ...
Gustavo de Souza's user avatar
1 vote
0 answers
31 views

Boundedness of an Integral Operator on $L^p(\mu)$

I realize this question has been asked way too many times, for instance, it's this exact problem which I will put below for convivence: Let $(X,\Omega, \mu)$ be a $\sigma$-finite measure space with $...
Isochron's user avatar
  • 1,399
2 votes
2 answers
95 views

With finite $\mu$, suppose $f_n$ converges in measure to $f$, and for all $n$, $||f_n||_2\leq 1$. Prove $||f_n-f||_1\rightarrow 0$

This is actually a part b), where part a) was to show $f\in L^2$. This was simple: as $f_n$ converges in measure to $f$, there exists a sub-sequence which converges $\mu$-a.e., thus Fatou's gives: $\...
cable's user avatar
  • 150
1 vote
1 answer
44 views

Does the weak limit of a sequence in $L^2([0,1])$ vanish on the limit set of vanishing sets?

Suppose $h_n$ is a sequence of non-negative functions in $L^2([0,1])$ converging weakly to $h$ (i.e., for every $g\in L^2([0,1])$ it holds $\int g\cdot h_n \,d\lambda \to \int g\cdot h\, d\lambda$). ...
Michael's user avatar
  • 365
1 vote
0 answers
219 views

$fg \in L^1$ for every $f \in L^2$ implies $g \in L^2$

Suppose that $f g$ is in $L^1([a,b])$ for every $f$ in $L^2([a,b])$, I understand that this implies that $g$ is in $L^2([a,b])$. Is this assertion true and, if so, how do I prove it? This question was ...
Alessandro's user avatar
1 vote
0 answers
32 views

Convergence on $L^1$ space

I come across this problem while reading hints for Exercise 3.15 (Brezis): Let $\Omega=(0,1)$ and sequence $f_n$ defined by $f_n(x)=ne^{-nx}$. Prove that: $$\displaystyle \int_{\Omega} \varphi f_n\...
Hải Nguyễn Hoàng's user avatar
1 vote
0 answers
119 views

Define multiplication on $L^1(\mathbb{R})$

I want to define multiplication on $L^1(\mathbb{R})$, of course, convolution is an allowed multiplication which makes $(L^1(\mathbb{R}),*)$ is a Banach algebra, I want to know if there are other ...
InnocentFive's user avatar
1 vote
1 answer
45 views

$p$-integrability of a certain Bessel function

I read the following statement in a book: $$ \frac{J_{\frac{n-2}{2}}(2\pi r)}{r^{\frac{n-2}{2}}}\text{ is in }L^p\text{ if and only if }p>\frac{2n}{n-1}\text{ ;} $$where $n\geq3$, $r$ is non-...
A. Bond's user avatar
  • 371
0 votes
0 answers
26 views

If $u\in L^\infty$, does the inequality $\int_\mathbb R u(x) |v(x)|^2 dx\le \|u\|_{L^\infty} \int_\mathbb R |v(x)|^2 dx$ hold true?

Let $u, v:\mathbb R\to\mathbb R^3$. Suppose that $u\in L^\infty(\mathbb R, \mathbb R^3)$ and $v\in L^2(\mathbb R, \mathbb R^3)$. Consider the integral $$\int_\mathbb R u(x) |v(x)|^2 dx.$$ The question ...
Physics user's user avatar

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