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0 votes
1 answer
53 views

Morse and Fesbach identity $\sum_{n=0}^{\infty} e^{-(n+\frac{1}{2})|u|} \; P_n(x) =(2\cosh u - 2x)^{-1/2}$

In book called Methods of theoretical physics from Morse and Feshbach, there is identity, which I wanted to prove ($P_n(x)$ are Legendre polynomials): $$\sum_{n=0}^{\infty} e^{-(n+\frac{1}{2})|u|} \; ...
Edward Henry Brenner's user avatar
0 votes
0 answers
69 views

Closed Forms for Sums of Legendre Polynomials

I am investigating a series of the form $$\sum_{n=0}^\infty \frac{1}{1 + e^{nx}}P_n(x)$$ where $P_n$ is the Legendre Polynomial of degree $n$. Because I am dealing with many of these series, it would ...
HtmlProg's user avatar
2 votes
1 answer
127 views

Asymptotic equality of $\frac{1}{n!}\frac{d^n}{dx^n}(x^n(1-x)^n) $

Consider the Shifted Legendre Polynomial $$\tilde P_n(x)=\frac{1}{n!}\frac{d^n}{dx^n}(x^n(1-x)^n) $$ where $n\in\mathbb{N}\cup\{0\}$ Question: What is the asymptotic equality of $\tilde P_n(x)$ as $n\...
Max's user avatar
  • 910
1 vote
1 answer
112 views

Showing that a series that involves Legendre polynomial converges.

I am currently studying Legendre polynomials and I am trying to prove its generating function specifically using the recurrence relation $$ (n+1)L_{n+1}(x) = x(2n+1)L_n(x) - nL_{n-1}(x), \quad \forall ...
xyz's user avatar
  • 1,141
2 votes
1 answer
89 views

Can order of summation and integral be interchanged in : $\int_{-1}^1 ( \sum_{n=0}^\infty P_n(\xi)P_n(\xi^\prime)Q_l(\xi^\prime))\text{d}\xi^\prime$?

I am wanting to know if there is a proof that the order of summation and integration can be interchanged in $$\int_{-1}^1 \left( \sum_{n=0}^\infty P_n(\xi)P_n(\xi^\prime)Q_l(\xi^\prime)\right)\text{d}\...
Joseph Robert Jepson's user avatar
0 votes
1 answer
174 views

Getting the recurrence relation for Legendre polynomials by Leibnitz rule

Exercise: For each natural number $n$ define $$\phi_n(x)=\frac{d^n}{d x^n}\left(x^2-1\right)^n$$ Derive the formulas $$\phi_{n+1}^{\prime}(x)=2(n+1) x \phi_n^{\prime}(x)+2(n+1)^2 \phi_n(x)$$ $$\phi_{n+...
emil agazade's user avatar
2 votes
1 answer
148 views

How to prove Legendre Polynomials' recurrence relation without using explicit formula?

Assume there is an inner product on linear space $V = \{ \text{polynormials}\}$: $$\langle f, g\rangle = \int_{-1}^1 w(t) f(t)g(t) dt$$ with $w(t) \ge 0$ and not identically zero. Then we can ...
maplemaple's user avatar
  • 1,231
1 vote
1 answer
270 views

How $x^n$ is linearly represented by Legendre polynomials

I recently come across a problem with respect to Legendre polynomial as follows. Let $L^2[-1,1]$ be the Hilbert space of real valued square integrable functions on $[-1,1]$ equipped with the norm $\|f\...
xiuhua's user avatar
  • 493
0 votes
1 answer
58 views

Exact value of an infinite sum expressed in terms of a product of definite integrals involving Legendre polynomials.

In a fluid mechanics problem, one has to deal with the following infinite sum: $$ S = \sum_{n \ge 1} \frac{2n+1}{n+1} \left( \int_0^1 P_n(x) \, \mathrm{d}x \right) \left( \int_0^1 x \left( 1-x^2\...
Siegfriedenberghofen's user avatar
2 votes
1 answer
292 views

How do I expand $\frac{1}{\sqrt{ (\boldsymbol{r-r'})^2+a} }$ in legendre polynomials (spherical harmonics)?

Using the generating function for the legendre polynomial: $$ \sum_{n=0}^{\infty} P_{n}(x) t^{n}=\frac{1}{\sqrt{1-2 x t+t^{2}}} $$ It's possible to expand the coulomb potential in a basis of legendre ...
sjm23's user avatar
  • 419
0 votes
1 answer
183 views

Shifted Legendre polynomials symmetry relation

I have to prove that $p_n(1-x)=(-1)^np_n(x)$ ($x\in[0,1]$) for all $n\in\mathbb{N}$, where $(p_n)_n$ is the family of Legendre polynomials on $[0,1]$: given $(x^n)_{n=0,1,\ldots}$, $(p_n)_n$ is the ...
UnusualMathem's user avatar
0 votes
2 answers
519 views

Convergence of Legendre Expansion in the Mean-Square sense.

I need to show that the Legendre Expansion converges to the function in the mean-square sense, here are some definitions. $$L_n(x)=\frac{d^n}{dx^n}(x^2-1)^n \text{ and } \mathfrak{L}_n(x)=\frac{L_n(x)}...
ASP's user avatar
  • 388
1 vote
0 answers
157 views

Orthogonality Legendre Polynomial WITHOUT integration by parts

I'm aware of the two questions [1] and [2] but I'm trying to proof the orthongonality of the Legendre polynomials without integration by parts. $$ \int_{-1}^1 P_\ell(x)P_{\ell'}(x) dx = \frac{2}{2\ell+...
Physor's user avatar
  • 4,644
1 vote
2 answers
2k views

Given the Rodrigues' formula for Legendre's polynomials, show that it satisfies the ODE.

The Rodrigues Formula for Legendre's Polynomials is $P_{l}(x)=\frac{1}{2^{l}l!}\frac{d^{l}}{dx^{l}}(x^2-1)^l$. I wrote $P_{l}(x)=\frac{1}{2^{l}l!}\frac{d^l}{dx^l}\sum_{k=0}^l(-1)^{k-l}\frac{l!}{k!(l-...
Dumbbbb's user avatar
  • 13
1 vote
1 answer
58 views

Differentiate $((x^{2}-1)f_{n-1}(x))^{(n)}$.

Differentiate $((x^{2}-1)f_{n-1}(x))^{(n)}$. Using Leibniz rule, I obtain the following: $\frac{x^{2}-1}{2^{n}n!}f_{n-1}^{(n)}(x)+\frac{x}{2^{n-1}(n-1)!}f_{n-1}^{(n-1)}(x)+\frac{1}{2^{n}(n-2)!}f_{...
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