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3 votes
1 answer
74 views

Legendre expansion of a root polynomial

What is the Legendre expansion of $\sqrt{1-x^2}$ ? I need a closed form. Thx. I have tried to reform it $$ \sqrt{1-x^2}=\left. \sqrt{1-2tx+x^2} \right|_{t=x} $$ while the generating function of ...
S'æntzee Groom's user avatar
2 votes
1 answer
567 views

Problem with Legendre-Fourier series for sinx when the number of terms approaches infinity

After I learned about Fourier series expansion, I understand orthogonality of trigonometric functions was the key when I calculate the coefficients of Fourier series. As I knew that Legendre ...
t0d4's user avatar
  • 23
0 votes
0 answers
400 views

Show that the inner product of the Legendre polynomials and $p\in L^2 ([-1,1])$ is equal to zero if the polynomial has degrees less than $n$

Let $(P_n )^{\infty}_{n=0}$ be the Legendre polynomials in $L^2([-1,1])$, normalised as $||P_n||^2=\frac{2}{2n+1}$. I need to show that, for any polynomial $p\in L^2([-1,1])$ with degree less than $n$,...
mp12853's user avatar
  • 174
1 vote
0 answers
127 views

Expand square of an associated Legendre polynomial in terms of simple associated Legendre Polynomials

I have an associated Legendre Polynomial $\left(P_l^m(\cos(\theta))\right)^2$ (where $l$ and $m$ are nonnegative integers). I need to find a way to express it in terms of simple associated Legendre ...
edgardeitor's user avatar
1 vote
0 answers
173 views

Expanding function on [0,1] using Legendre polynomials

A quick question. Given a boundary condition that a function $f(x)=\sum_{n=0}^\infty a_n P_{2n+1}(x)$ , which is defined for $x$ in $[0,1]$, not for $-1$ to $1$. I know the standard Fourier- Legendre ...
Chang Henry's user avatar
0 votes
1 answer
213 views

Fourier-Legendre series - Need answers for all 5 question marks

Let $f(x)= |x|$ on $-1\leq x\leq 1$. Then there is a Fourier-Legendre expansion $f(x)$ = $\sum_{m=0}^{\infty} c_mP_m(x)$ where $P_n(x) = \frac{1}{2^n n!} \frac{d^n}{dx^n} \left[(x^2-1)^n\right]$ $c_0 ...
aMATHcheur's user avatar
5 votes
1 answer
207 views

Showing a summation identity for $1$, possibly tied to Legendre polynomials

The Problem: Consider the sign function on $(-1,0)\cup(0,1)$ defined by $$ \sigma(x) := \left. \text{sgn}(x) \right|_{(-1,0)\cup(0,1)} = \begin{cases} 1 & x \in (0,1) \\ -1 & x \in (-1,0) \end{...
PrincessEev's user avatar
  • 45.9k
3 votes
0 answers
563 views

Why the expansion of functions of 2 variables in legendre polynomials does not take into account all products Pi (x) Pj (y)?

My question arises from this reading link (In this article, in equation 6 on page 3, also expands a function of 2 variables in this way Parametric estimate of intensity inhomogeneities applied to MRI),...
Roger Figueroa Quintero's user avatar
0 votes
1 answer
545 views

Fourier-Legendre series

I am given a function of $\theta$ as $$f(\theta)=\ln\left(\dfrac{1+\sin\frac\theta2}{\sin\frac\theta2}\right)$$ and I am asked to express this function as a Fourier-Legendre series of the form $\sum_{...
Someone's user avatar
  • 2,885
0 votes
1 answer
159 views

Find the value $P_n(1)$ of the Legendre polynomials from their generating function

Here is the question: Using $\sum_{n=0}^{\infty}P_n(x)r^n=(1-2rx+r^2)^{-\frac{1}{2}}$ find the value of $P_n(1)$ I am unsure how to handle this question. I did the following and would like ...
Lauren Bathers's user avatar
2 votes
2 answers
339 views

Intuition for polynomial bases

In my linear algebra course I stumbled upon the following observations. We have some function $f: \Bbb{R} \to \Bbb{R}$, $f = f(x)$. $f(x)$ may be composed of elementary functions or not, but in ...
user01101001's user avatar
0 votes
1 answer
53 views

Find a recurrence relationship for the following :

Find a recurrence relationhip for $a_{n}$: $a_{n}=\dfrac {2n+1}{2}\int^{1}_{-1}f\left( x\right) P_{n}\left( x\right) dx$ Where $f\left( x\right)= e^{-x}$ I have done it many times and keep ...
Tom Otto's user avatar
  • 379
0 votes
1 answer
360 views

Find a recurrence relation and the Fourier-Legendre Series

Rodrique's Formula for the $n$th Legendre Polynomial is $$P_n\left(x\right)=\dfrac{1}{2^nn!}\dfrac{d^n}{dx^n}\left(\left(x^2-1\right)^n\right)$$ The Fourier-Legendre series of a function f is ...
Sophie Filer's user avatar
1 vote
1 answer
226 views

Integrate the Fourier Legendre by parts :$\int_{-1}^{1}\left( x^{2}-1\right) ^{m}\cos \pi x\:dx$

Having difficulty integrating the Fourier Legendre series by parts : $$\alpha_{m}=\int_{-1}^{1}\left( x^{2}-1\right) ^{m}\cos \pi x\:dx$$ I understand we can use the general formula : $$uv-\int ...
Tom Otto's user avatar
  • 379
2 votes
1 answer
683 views

Use integration by parts to verify the following :

Using integration by parts show that: $\int^{1}_{-1}P_{n}\left( x\right) P_{m}\left( x\right) dx$ = $\dfrac {2}{2n+1}, m=n$ and $0$ if $m\neq n$ Where the functions are both Legendre polynomials. ...
Tom Otto's user avatar
  • 379

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