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5 votes
3 answers
1k views

Proving that odd partitions and distinct partitions are equal

I am working through The Theory of Partitions by George Andrews (I have the first paperback edition, published in 1998). Corollary 1.2 is a standard result that shows that the number of partitions of $...
seeker_after_truth's user avatar
3 votes
1 answer
85 views

Showing $\prod_{n\geq 1} (1+q^{2n}) = 1 + \sum_{n\geq 1} \frac{q^{n(n+1)}}{\prod_{i=1}^n (1-q^{2i})}$

I want to show \begin{align} \prod_{n\geq 1} (1+q^{2n}) = 1 + \sum_{n\geq 1} \frac{q^{n(n+1)}}{\prod_{i=1}^n (1-q^{2i})} \end{align} I know one proof via self-conjugation of partition functions with ...
phy_math's user avatar
  • 6,490
0 votes
1 answer
47 views

Infinite product formula for $\sum_{n \geq 0} p_e(n)\cdot x^n$

If $n$ is an integer and $p_e(n)$ is the number of partitions for $n$ such that all parts are even, what would be an infinite product formula for $\sum_{n \geq 0} p_e(n)\cdot x^n$
hoya2021's user avatar
  • 101
2 votes
1 answer
943 views

Proof that the series for the generating function of the partition function converges?

For $|q| < 1$, the generating function of the partition function $p(n)$ is given by $$ \sum_{n=0}^\infty p(n) q^n = \prod_{k=1}^\infty {1 \over 1-q^k}. \tag{1} $$ I have an intuitive ...
A l'Maeaux's user avatar
7 votes
1 answer
171 views

Generating function for $r^\binom{n}{2}$

I'm trying to find a closed form of the generating function $$ G(x) = \sum_{n \ge 0} r^\binom{n}{2} x^n $$ for a real number $0 < r < 1$. I found that $G(x) = 1 + xG(rx)$. Any hints where to ...
Snowball's user avatar
  • 3,078