All Questions
Tagged with ideals integral-domain
75
questions
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55
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How Should I show that these $k$-algebras are not Isomorphic?
Question
Show that the $k$-algebras $k[x,y]/\langle xy \rangle$ and $k[x,y]/\langle xy-1 \rangle$ are not isomorphic.
Attempt
At first, I thought $xy=0$. This would mean both $x$ and $y$ are zero ...
1
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0
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$R = \mathbb R[X,Y]/(XY - 1)$ and $I$ be the ideal of $R$ generated by the image of the element $X - Y$ in $R$. Describe $R/I$
Let $R = \mathbb R[X,Y]/(XY - 1)$ ($\mathbb R$ is the set of real numbers) and I be the ideal of R generated by the image of the element X - Y in R.
I want to find a way to describe R/I, i.e. find a ...
2
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0
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93
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Is $(I(R:_{Q(R)} I))^n$ generated by $(fI)^n$ as $f$ varies over $(R:_{Q(R)} I)$?
Let $(R, \mathfrak m)$ be a Noetherian local domain of dimension $1$ which is not a UFD. Let $Q(R)$ be the fraction field of $R$. If $I\subsetneq \mathfrak m$ is a non-zero, non-principal ideal of $R$ ...
4
votes
1
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125
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Counterexample of Divisibility of Ideals with Product of Ideals
Given a commutative ring $R$ with unity, we define for $I,J\subseteq R$ ideals
$I\ \vert\ J\iff I\supseteq J$
$IJ=\{\sum_i a_ib_i:a_i\in I, b_i\in J\}$
For every commutative unitary ring $R$ it ...
1
vote
1
answer
58
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ID's, PID's, Noetherian rings and valuation rings: implications amongst them
I am trying to establish some implications between being an ID, a PID, a Noetherian ring and a valuation ring.
First of all, I know that PID $\Rightarrow$ Noetherian, because in a PID every ideal is ...
0
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1
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130
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If $R$ is a ring such that $\forall x\in R, x^n=x$ for some $n>1$ then when $P$ is prime, why is $R/P$ finite?
I was recently reading a post on MSE which had an argument like:
If $P$ is a prime ideal of a ring $R$ all of whose elements satisfy $x^n = x$, then $R/P$ is an integral domain with the same property....
0
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1
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58
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Free submodules of an integral $R.$
I was told by the author of the answer here Showing that the rank of $M$ is exactly $1.$ that: Free submodules of an integral domain $R$ are exactly the principal ideals of $R.$
I am wondering which ...
1
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0
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53
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Is $I^n \not = I^{n+1}$ for all non-zero proper ideals $I$ of an integral domain? [duplicate]
For $R$ a (commutative with 1) integral domain, is it possible to have $I^n = I^{n+1}$ for some non-zero proper ideal $R$? I realise that in the case of a Noetherian domain, we can apply Krull's to ...
0
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1
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112
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Does the ring $k[x,y,z,w]/(wx-yz)$ contain nonconstant invertible polynomial?
Problem: Let $k$ be an algebraically closed field, $k[x,y,z,w]$ be polynomial ring, and $(wx-yz)$ be the ideal generated by $wx-yz$. Does $A(X):= k[x,y,z,w]/(wx-yz)$ contain any nonconstant invertible ...
0
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1
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20
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Question related to infinitely generated ideals
Let $A$ be a domain and $X \subset A$. Then
$(X) = \{a_1x_1 + \cdots + a_nx_n \mid
n \in \mathbb{N},\, a_i \in A,\, x_i \in X\}$
What I understand from the above theorem is that if $x\in X$ then ...
0
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1
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61
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Equality of principal domains $(a) = (b)$ does not imply that $a = bu$ for some unit $u$. [duplicate]
I proved that in an integral domain that the implication always holds, but apparently it doesn't necessarily hold in all rings, and I have been looking for counterexamples. But, I'm confused why this ...
1
vote
1
answer
85
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Is it really necessary to work with the fraction field here?
Let $A$ be an integral domain, $\mathfrak{p}$ a prime ideal of $A$. Let $f(X)=a_nX^n+...+a_1X+a_0$ be a primitive and non constant polynomials of $A[X]$. We also suppose that $a_k \in \mathfrak{p}$ ...
2
votes
2
answers
169
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r-ideals in commutative rings
I'm learning about r-ideals in commutative rings from a journal by Rostam Mohammadian.
"A proper ideal I in a ring R is called an r-ideals (resp., pr-ideal), if ab is an element in I with ann(a)=<...
1
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1
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909
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Find the kernel of a homomorphism between polynomial rings
Specifically, I'm trying to solve the following problem:
Let $R$ be an integral domain and let $x$, $y$ and $t$ be indeterminates. Let $R[x,y]$ denote the ring of polynomials in $x$ and $y$ over $R$...
3
votes
4
answers
527
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Integral Domains and Maximal Ideals
I need to show that if $R$ is an integral domain (containing three ideals: $\{0\}$, $I$ and $R$), then $a,b\in I\Rightarrow ab=0$.
I know that since $R$ is an integral domain, $ab=0\Leftrightarrow a=...