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1 vote
0 answers
55 views

Writing momentum 4vector as an integral over the EM stress-energy tensor

I have been watching a series of lectures on general relativity by Neil Turok and I have run into a problem. In one of the lectures, the professor writes the momentum 4-vector as a contraction of the ...
Jesse Van Der Kooi's user avatar
0 votes
0 answers
44 views

Finding the change of basis matrix for a type (0,1) tensor

I am considering a tensor (in particular, the electric field), defined by $$E_m = g_{ij}^k c_{k\ell}^{ij}S_{\ell m} $$ Ultimately, this means that the tensor E is a rank 1, type (0,1) tensor, ...
Luk'yan Vilshansky's user avatar
0 votes
2 answers
113 views

Formula for the Maxwell Stress tensor in arbitrary coordinates

This question is nearly identical to my last, except this time its the Maxwell stress tensor, not the Cauchy stress tensor. I often see its components written as $$\sigma_{ij}=\varepsilon_0E_iE_j+\...
K.defaoite's user avatar
  • 12.5k
2 votes
0 answers
52 views

Is there a way to represent electrostatics tensors in tensor (possibly tensor product) way?

I'm working with electrostatic interaction tensors, which are defined as follows: \begin{align} T &= \frac{1}{r} \\ T^\alpha &\equiv \nabla T = -\frac{r^\alpha}{r^3} \\ T^{\alpha\...
Bbllaaddee's user avatar
1 vote
1 answer
616 views

Why does the electromagnetic tensor in component form coincide with the differential-geometric definition of a $2$-form?

From physics classes, I understand the electromagnetic field strength tensor to be defined as $$F^{\mu\nu}=\partial^\mu A^\nu-\partial^\nu A^\mu \;,$$ where $\partial^\mu$ is the partial derivative (...
Ali's user avatar
  • 157
0 votes
1 answer
167 views

Gradient in tensor form

I found a problem which had $$\partial_i (A_i \vec{G})= (\vec{\nabla} .\vec{ A} )\vec{G}+ (\vec{A}.\nabla) \vec{G} $$ but my problem is what does $$\partial_i (A_i \vec{B})$$ even mean? it doesn't ...
SHIN101's user avatar
  • 11
2 votes
0 answers
41 views

Show that $\nabla . *F = 0$ is a geometric frame independent of ...

Show that $\nabla\cdot\ast F = 0$ (divergence of the dual of the EMF tensor) is a geometric frame independent version of $F_{ab,c} + F_{bc,a} + F_{ca,b} = 0$, where $F$ is the electromagnetic field ...
Lac's user avatar
  • 761
1 vote
0 answers
90 views

Unconstrained quartic optimization

I am working on antenna array pattern synthesis algorithms, and am trying to minimize the following expression with respect to $\mathbf{v}$ $$ \int_\Omega \Big[ \big( \mathbf{v}^H \mathbf{Y}(\vartheta,...
donnonothin's user avatar
2 votes
1 answer
645 views

Find directions where current is maximal

The current $J_i$ due to an electric field $E_i$ is given by $J_i = σ_{ij} E_j$ , where $σ_{ij} is the conductivity tensor. In a given Cartesian coordinate system, $σ=\begin{pmatrix}2&-1&-1 \\...
John Smith's user avatar
1 vote
1 answer
357 views

Tensor manipulation involving Levi-Cevita tensor

I am attempting to follow a derivation from a physics paper relating to covariant electromagnetism. It is given that, $$ F^{\mu \nu} = u^{\mu}E^{\nu} - E^{\mu} u^{\nu} + \epsilon^{\mu \nu \alpha \...
user1887919's user avatar
2 votes
1 answer
1k views

Showing that no current flows in some direction, given $\sigma_{ij}$ and that $J_i=\sigma_{ij}E_j$.

The current $J_i$ due to an electric field $E_i$ is given by $J_i=\sigma_{ij}E_j$, where $\sigma_{ij}$ is the conductivity tensor. In a certain coordinate system, $$(\sigma_{ij})=\begin{pmatrix} 2&...
Aka_aka_aka_ak's user avatar