Skip to main content

All Questions

Tagged with
2 votes
2 answers
183 views

Does an odd perfect number have a divisor (other than $1$) which must necessarily be almost perfect?

Let $\sigma(x)=\sigma_1(x)$ be the classical sum of divisors of the positive integer $x$. Denote the aliquot sum of $x$ by $s(x)=\sigma(x)-x$ and the deficiency of $x$ by $d(x)=2x-\sigma(x)$. ...
Jose Arnaldo Bebita Dris's user avatar
0 votes
2 answers
102 views

Is there an analytical solution to the inequality $\frac{1 + k({p}^{(k+1)/2)})}{p^k} < \frac{p}{p - 1}$ if one were to bound $k$ in terms of $p$?

My question is as is in the title: Is there an analytical solution to the inequality $$\frac{1 + k({p}^{(k+1)/2)})}{p^k} < \frac{p}{p - 1}$$ if one were to bound $k$ in terms of $p$? Here, $p \...
Jose Arnaldo Bebita Dris's user avatar
0 votes
1 answer
94 views

If $p$ is a prime number and $k$ is a positive integer, is it true that $\sigma_1(p^k) > 1 + k (\sqrt{p})^{1+k}$?

Denote the classical sum of divisors of the positive integer $x$ by $\sigma(x)=\sigma_1(x)$. Here is my initial question: If $p$ is a prime number and $k$ is a positive integer, is it true that $$\...
Jose Arnaldo Bebita Dris's user avatar
1 vote
1 answer
223 views

Can this inequality involving the deficiency and sum of aliquot divisors be improved? - Part II

This MSE question (from April 2020) asked whether the inequality $$\frac{D(n^2)}{s(n^2)} < \frac{D(n)}{s(n)}$$ could be improved, where $D(x)=2x-\sigma(x)$ is the deficiency of the positive integer ...
Jose Arnaldo Bebita Dris's user avatar
0 votes
4 answers
100 views

Does $\frac{\sigma(q^k)}{n} + \frac{\sigma(n)}{q^k} < 10$ hold in general for an odd perfect number $q^k n^2$ with special prime $q$?

This question is an offshoot of this MSE answer. Let $\sigma(x)$ be the sum of the divisors of the positive integer $x$. (Denote the abundancy index of $x$ by $I(x)=\sigma(x)/x$.) If $\sigma(M) = 2M$...
Jose Arnaldo Bebita Dris's user avatar
0 votes
3 answers
193 views

On the conjectured inequality $q > k$, where $q^k n^2$ is an odd perfect number with special prime $q$

Let $N=q^k n^2$ be an odd perfect number with special/Eulerian prime $q$ satisfying $q \equiv k \equiv 1 \pmod 4$ and $\gcd(q,n)=1$. Descartes, Frenicle, and subsequently Sorli conjectured that $k=1$ ...
Jose Arnaldo Bebita Dris's user avatar
1 vote
1 answer
115 views

If $N = q^k n^2$ is an odd perfect number with special prime $q$, then must $\sigma(n^2)$ be abundant?

Preamble: This post is an offshoot of this earlier MSE question. The topic of odd perfect numbers likely needs no introduction. Let $\sigma=\sigma_{1}$ denote the classical sum of divisors. Denote ...
Jose Arnaldo Bebita Dris's user avatar
1 vote
0 answers
76 views

On the sum $I(q^k) + I(n^2)$, where $q^k n^2$ is an odd perfect number with special prime $q$

Denote the classical sum of divisors of the positive integer $x$ by $\sigma(x)=\sigma_1(x)$, and denote the abundancy index of $x$ by $I(x)=\sigma(x)/x$. Let $N = q^k n^2$ be an odd perfect number ...
Jose Arnaldo Bebita Dris's user avatar
1 vote
0 answers
37 views

Does this "improvement" to $I(m) < 2$, if $p^k m^2$ is an odd perfect number with special prime $p$, work?

(Preamble: This question is an offshoot of this earlier post.) Denote the classical sum of divisors of the positive integer $x$ by $\sigma(x)=\sigma_1(x)$, and the abundancy index of $x$ by $I(x)=\...
Jose Arnaldo Bebita Dris's user avatar
2 votes
2 answers
217 views

If $p^k m^2$ is an odd perfect number with special prime $p$, then which is larger: $D(p^k)$ or $D(m)$?

(Preamble: This question is tangentially related to this earlier post.) Denote the classical sum of divisors of the positive integer $x$ to be $\sigma(x)=\sigma_1(x)$. Denote the abundancy index of $...
Jose Arnaldo Bebita Dris's user avatar
2 votes
1 answer
133 views

If $p^k m^2$ is an odd perfect number with special prime $p$, then which is larger: $D(p^k)$ or $D(m^2)$?

Denote the classical sum of divisors of the positive integer $x$ to be $\sigma(x)=\sigma_1(x)$. Denote the abundancy index of $x$ by $I(x)=\sigma(x)/x$. Finally, denote the deficiency of $x$ by $D(x)...
Jose Arnaldo Bebita Dris's user avatar
0 votes
1 answer
189 views

Why does an odd perfect number seemingly "violate" basic inequality rules?

Let $p^k m^2$ be an odd perfect number (OPN) with special prime $p$ satisfying $p \equiv k \equiv 1 \pmod 4$ and $\gcd(p,m)=1$. My question is as is in the title: Why does an OPN seemingly "...
Jose Arnaldo Bebita Dris's user avatar
1 vote
2 answers
116 views

On a curious equation regarding odd perfect numbers

Let $p^k m^2$ be an odd perfect number (OPN) with special prime $p$ satisfying $p \equiv k \equiv 1 \pmod 4$ and $\gcd(p,m)=1$. Since $\gcd(p^k, \sigma(p^k))=1$, then we essentially get the equation $$...
Jose Arnaldo Bebita Dris's user avatar
1 vote
3 answers
238 views

If $p^k m^2$ is an odd perfect number, then what is the optimal constant $C$ such that $\frac{\sigma(m^2)}{p^k} < \frac{m^2 - p^k}{C}$?

The topic of odd perfect numbers likely needs no introduction. The question is as is in the title: If $p^k m^2$ is an odd perfect number with special prime $p$, then what is the optimal constant $C$ ...
Jose Arnaldo Bebita Dris's user avatar
2 votes
1 answer
46 views

Does this inequality hold for all odd $n$: $\sigma_{n-1}\sigma_{n+3} > \sigma_{n}\sigma_{n+2}$?

Let be $\sigma_n = \sum\limits_{d|n}d$ and let $n$ be an odd number, then the following inequality holds numerically up to $n = 10^7$. $$ \begin{align} \sigma_{n-1}\sigma_{n+3} > \sigma_{n}\sigma_{...
thinkingeye's user avatar

15 30 50 per page
1
2 3 4 5 6