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0 votes
0 answers
43 views

Question On Function Growth rate

Assume we have the grow rate of $log(n^{2n})$, $log(n!)$, $n(log(n))^3$, $n(2^n)$, $n^{(1.5)}$,$n^{(log(log(n)))}$,$\sqrt{2^{log(n)}}$,$2^{(\sqrt{log(n)})}$,$2^{(log\sqrt{n})}$,$2^{(2n)}$, $(log(n))!$ ...
Kensh1n's user avatar
1 vote
3 answers
238 views

What actually growth of a function represents?

I am going through the book Discrete Mathematics by Kenneth Rosen. In chapter 3, there is a topic "The Growth of Functions" and then Big-O Notation. I am really unable to understand what ...
monalisa's user avatar
  • 4,470
0 votes
3 answers
131 views

How to show properly $ 10n^4 + 3n^3 -n \in O(n^4)$?

Given: $$ 10n^4 + 3n^3 -n \in O(n^4)$$ So i do understand Big O and what it does. I am however not quite if my approach for the solution is correct, so anyone who could help me out or show me an ...
JohnGam's user avatar
  • 331
0 votes
2 answers
65 views

one doubt on big oh notation

I see an example that $f(n)=O(n)$ and $\sum_{i=1}^nf_i(n)=O(n^2) $ in which $f_i$ is a function from natural to natural number. I ran into a challenge, that above notation is differ from the ...
Lara Kat's user avatar
0 votes
1 answer
46 views

maybe crazy question on asymptotic notation

I see two time complexity. $O ( m (\log m + \log n))$ and $O(m \log m \log n)$. Is it correct that according to logarithm rules tell these are equals A) from asymptotic view and B) from math point of ...
M K's user avatar
  • 27
1 vote
4 answers
459 views

$ \sqrt n \log \sqrt n$ is lower than $n$ ?!

I see an example in asymptotic notation that not very sensible for me. what is the intuitive idea to understand $ \sqrt n \log \sqrt n$ is lower than $n$ in concept of asymptotic view?
M K's user avatar
  • 27
1 vote
1 answer
57 views

How little o can verify for one example?

I have following facts: $n^2log_2n+n^2$ = $o(n^3)$ how I can understand this is true fact? I'm not rain into a homework question, any intuitively idea to quickly find or doing by math?
Jessica Allen's user avatar
1 vote
1 answer
207 views

two asymptotic comparison on sparse graph and misunderstanding point

I read in my notes: if we use Dijkstra $|V|$ times ($|V|$ number of vertexes) for finding all pairs shortest paths in graph $G$, We get time complexity for Dijkstra algorithm as $O(VE+ V^2 log V)$ and ...
S. Christin's user avatar
2 votes
1 answer
28 views

asymptotic statement and one example

how I can logically understand this is false ($c$ is constant): $ \frac{n!}{c} \leq 2^n$ why it was false for large value from asymptotic notation concept? ( i see this is true for some $n < n_0$ ...
Betty Andersson's user avatar
0 votes
1 answer
220 views

Some big-theta and big-omega notation question

Let $f : \mathbb{N} \rightarrow \mathbb{R}$ be the function $f ( n ) = n ^ { 2 } + \sqrt { n }$. Determine whether the following statement is true or false, providing a proof for your answer. $ f(n) =...
Antonymous's user avatar
0 votes
0 answers
23 views

Asymptotic relation between $n^2 (n-2\lfloor \frac{n}{2} \rfloor)$ and $2\lfloor \frac{n}{2} \rfloor$

What is asymptotic relation between $n^2 (n-2\lfloor \frac{n}{2} \rfloor)$ and $2\lfloor \frac{n}{2} \rfloor$? My attempt: let $\lfloor \frac{n}{2} \rfloor = n$. Then the equation comes down to $n^3 ...
underdisplayname's user avatar
0 votes
2 answers
272 views

How to prove $n^6$ is big-O but not big-Omega of the function $(1.001)^n$

I know that, $n^c \in \mathcal{O}(2^n)$ for any constant $c$. However, I don't know how to prove, or whether it is correct that, $n^c \in \mathcal{O}(1.001)^n$ for any constant $c$. Does anyone has ...
underdisplayname's user avatar
0 votes
1 answer
154 views

Time complexity of an iterative function related to bits

I am wondering about correct answer to this task from a test earlier today: A function Pow which calculates $y = a^k$ is given, where $k$ is an integer of ...
weno's user avatar
  • 1,392
0 votes
1 answer
29 views

Prove whether $f(n)$ is $O$, $o$, $\Omega$, $\omega$ or $\Theta$ of $g(n)$.

$f(n) = e^{n} \ln(n)$, $g(n) = 2^{n} \log(n)$ log can be assumed to be base $2$. Alright so I put this in the form $f(n) / g(n)$ and then used L'Hôpital's rule giving me $$ \frac { \dfrac{e^n}{n} +...
Brownie's user avatar
  • 667
0 votes
0 answers
25 views

Is this solution correct? Prove whether $f(n)$ is $O$, $o$, $\Omega$, $\omega$ or $\Theta$ of $g(n)$

$f(n) = n + (\log n)^{2}$, $g(n) = n + \log(n^{2})$. log is assumed to be base 2 So I differentiated each of the functions $f(n)' = 1 + 2(\log n)$ $g(n)' = 1 + (2/n\ln(2))$ and then finding the ...
Brownie's user avatar
  • 667

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