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3 votes
1 answer
238 views

Alternating Dirichlet series involving the Möbius function.

It is well known that: $$\sum_{n=1}^\infty \frac{\mu(n)}{n^s} = \frac{1}{\zeta(s)} \qquad \Re(s) > 1$$ with $\mu(n)$ the Möbius function and $\zeta(s)$ the Riemann Zeta function. Numerical ...
Agno's user avatar
  • 3,191
0 votes
1 answer
49 views

What is the Dirichlet serie of The function $A$ (OEIS A001414) which gives the sum of prime factors (with repetition) of a number $n$?

The function $A$ (OEIS A001414) which gives the sum of prime factors (with repetition) of a number $n$ and defined by $$ A(n)=\sum \limits_{p^{\alpha}\parallel n}\alpha p $$ is this serie calculated ...
Es-said En-naoui's user avatar
0 votes
0 answers
117 views

Perron's formula application - zeros of $L(s,\chi )$

After applying Perron's formula I have a complex integral involving something like \[ \sum _{n=1}^\infty \frac {\mu (n)}{n^s}e\left (\frac {an}{q}\right ).\] As usual ("usual" meaning e.g. ...
tomos's user avatar
  • 1,662
0 votes
1 answer
96 views

Need help with finding Dirichlet generating function

I am unable to find the following generating function: $$\tag{1}{\sum _{n=1}^{\infty } \frac{2^{-k_n} \mu \big(\frac{n}{2^{k_n}}\big)}{n^s}}$$ $\mu$ is Möbius function, $k_n$ is the highest integer ...
azerbajdzan's user avatar
  • 1,206
1 vote
2 answers
235 views

Prove $\sum_{d | n} \mu(d) (\log(d))^2=0$ [duplicate]

If $n$ is a positive integer with more than 2 distinct prime factors, how to prove that $\sum_{d | n} \mu(d) (\log(d))^2=0$? I struggle on how to continue from this. Suppose $n=p_1 p_2 ... p_r$, ...
Eug's user avatar
  • 21
1 vote
0 answers
52 views

Variant of Möbius inversion: $b(n) = \sum_{d^2 \mid n} a(n/d^2) d^\alpha$

I'm trying to understand a step in a classic paper of Rankin. In Rankin's paper Contributions to the theory of Ramanujan's function $\tau(n)$ and similar arithmetical functions, he defines $$ b(n) := \...
dld's user avatar
  • 11
0 votes
3 answers
109 views

Proving identity using Dirichlet L functions

I'm trying to prove the following identity using Dirichlet L functions : ${\displaystyle \sum _{d\mid n}\varphi (d)=n}$ I have shown proved that the Dirichlet Series of $\varphi (n)$ equals to ${\...
BOB123's user avatar
  • 105
2 votes
0 answers
113 views

Question about Dirichlet Series Related to Formula for $\frac{1}{e}$

This question is related to the three functions defined in (1) to (3) below where $\coth(z)$ gives the hyperbolic cotangent of $z$. (1) $\quad M(x)=\sum\limits_{n=1}^x\mu(n)\quad\text{(Mertens ...
Steven Clark's user avatar
  • 7,631
0 votes
1 answer
84 views

Questions on $f(x)=\sum\limits_{n=1}^{x}a(n)$ with an infinite number of positive integer zeros

This question is related to a class of functions that meet the following conditions. (1) $\quad f(x)=\sum\limits_{n=1}^{x}a(n)$ (2) $\quad f(x)=0$ for an infinite number of values of $x\in\mathbb{Z}^...
Steven Clark's user avatar
  • 7,631
0 votes
1 answer
378 views

Dirichlet series for 1/ζ(s)

Prove that for Re(s)>1 $$\frac{1}{\zeta(s)}=\sum_{n=1}^{\infty}\frac{\mu(n)}{n^s}$$ Where $\mu(n)$ is the Möbius function defined by: $\mu(n)=1, \mbox{if }n=1$ $\mu(n)=(-1)^k, \mbox{if }n=p_1,p_2,....
tererecomchimarrao's user avatar
1 vote
1 answer
1k views

Dirichlet Series of Absolute value of Mobius Function equals Ratio of Riemann Zeta

I would like to prove this using Euler products: $$\frac {\zeta(s)}{\zeta(2s)} = \sum_{n=1}^{\infty}\frac {\lvert \mu(n) \rvert}{n^s}$$ I have gotten here, but don't know if this is a correct ...
Amour's user avatar
  • 395
3 votes
1 answer
152 views

Is known the function $\sum_{n=1}^\infty\frac{(-1)^n\mu(n)}{n^s}$, where $s$ is the complex variable and $\mu(n)$ the Möbius function?

Let $\mu(n)$ the Möbius function, see its definition for example from this MathWorld, and we denote with $s$ the complex variable. I'm curious to know if some case of the series $$\sum_{n=1}^\infty\...
user avatar
1 vote
1 answer
64 views

On $\frac{1}{2\pi i}\int_{c-i\infty}^{c+i\infty}\eta'(s)\frac{x^s}{s\zeta(s)}ds$, for $c>1$, where $\eta(s)$ is the Dirichlet Eta function

When I was combining the identities from this article from Wikipedia for the Mertens function, I've asked my an open question, if you can solve it from a standard viewpoint it is appreciated, and ...
user avatar
6 votes
1 answer
503 views

Is this Dirichlet "$\eta$ version" of the inverse relationship between $\zeta(s)$ and the Möbius function correct?

With $\mu(n)$ the Möbius function and $\zeta(s)$ the Riemann zeta function, it is well-known that: $$\frac 1{\zeta(s)}=\sum_{n=1}^\infty \frac{\mu(n)}{n^s}$$ that is proven to converge for $\Re(s)&...
Agno's user avatar
  • 3,191
6 votes
2 answers
732 views

Dirichlet series associated to squared Möbius

I would like to estimate the Dirichlet series of a multiplicative function. Consider the following: $$\sum_{m \leqslant X} \frac{\mu^2(m)}{m^s}$$ When does it converges when $X$ grows? What is an ...
Desiderius Severus's user avatar

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