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2 votes
2 answers
88 views

Does convolution preserve local integrability in the sense that if $f \in L^p_{\text{loc}}$ and $g \in L^1$, then $f \ast g \in L^p_{\text{loc}}$?

Consider the Euclidian space $\mathbb R^n$, where $n \in \mathbb N$ is a fixed integer, equipped with the Lebesgue measure. Let $L^p_{\text{loc}}(\mathbb R^n)$($1 \leqslant p < \infty$) denote the ...
xyz's user avatar
  • 1,141
0 votes
0 answers
47 views

$g: R \to R$ is integrable and has compact support. $f(y) =sin^2(y) ln|y|$. Show that $(f ∗ g)(x)$ is well defined for $x \in R$ and of class $C^1$?

$g : \mathbb{R} \to \mathbb{R}$ is integrable over $\mathbb{R}$ and has a compact support. $f(y) = \sin^2(y) \ln|y|$ Show that the convolution $(f ∗ g)(x)$ is well defined for $x \in \mathbb{R}$ and ...
thefool's user avatar
  • 1,096
4 votes
1 answer
81 views

Convergence of the difference of the convolution of sequence of functions and a function

Let $(g_j)_{j \in \mathbb{N}} \subseteq \mathscr{L}_1(\mathbb{R}^n)$ with $\|g_j\| = 1$ and $g_j \geq 0$ for all $j \in \mathbb{N}$. Suppose that $\lim_{j \to \infty} d_j = 0$ where $d_j := \sup\{\|x\|...
Kham Bodrogi's user avatar
1 vote
0 answers
119 views

Define multiplication on $L^1(\mathbb{R})$

I want to define multiplication on $L^1(\mathbb{R})$, of course, convolution is an allowed multiplication which makes $(L^1(\mathbb{R}),*)$ is a Banach algebra, I want to know if there are other ...
InnocentFive's user avatar
2 votes
1 answer
75 views

Differentiability of convolution without compact support

Let $g \in C^1(\mathbb R), f, g, g' \in L^1(\mathbb R)$. How do I then show $f * g$ is differentiable? Variations of this question have been asked where $g$ or $g'$ have compact support, but these ...
univalence's user avatar
0 votes
0 answers
82 views

About the Convex Hull of a the image of a function

Let $ f \in L^1_{loc}(\mathbb R^n)$ and $ \varphi $ a mollifier, consider $\varphi_{\varepsilon}:=\frac{1}{\varepsilon ^n} \varphi \left( \frac{x}{\varepsilon} \right)$ show that $f * \varphi_{\...
C L 's user avatar
  • 311
2 votes
0 answers
37 views

Prove that if either $f \in (L^p \cap C^m)(\mathbb{R}^n)$, or $g \in (L^q \cap C^m)(\mathbb{R}^n)$, then $f \ast g \in C^m$

Let $1 \leq p \leq \infty$, with $\frac{1}{p} +\frac{1}{q}=1$. Show that if $f \in L^p(\mathbb{R}^n)$ and $g \in L^q(\mathbb{R}^n)$, then a) The convolution $f\ast g$ is bounded and continuous on $\...
Mr. Proof's user avatar
  • 1,575
1 vote
1 answer
124 views

Compound Poisson Distribution and its Expected Value

I am trying to understand the proof of Theorem 16.14 of Probability Theory by A. Klenke (3rd version) about the Levy-Khinchin formula. I would like to know how to prove this: $$E[X]=\int x e^{-v(\...
Enrico's user avatar
  • 563
3 votes
0 answers
79 views

Differentiating under the integral sign in $n$ variables to show $\partial^{\alpha}(f*g)=f*\partial^{\alpha}g$

As an easy corollary of Dominated Convergence theorem, Folland gives a criterion for differentiating under the integral sign and uses it to prove Proposition $8.10$: Proposition $8.10:$ If $f \in L^1$...
miyagi_do's user avatar
  • 1,777
0 votes
1 answer
470 views

Uniform Convergence of Convolution of $f$ and Good Kernel

My task is to prove that if $f$ is continuous on $\mathbb{R}^d$ with compact support and $\{K_\delta\}_{\delta>0}$ is a family of good kernels then $f \ast K_\delta \xrightarrow{\text{unif.}} f$ as ...
YessuhYessuhYessuh's user avatar
3 votes
0 answers
92 views

Convolution derivative, $(f*g)'=f*g'$

Let $f,g \in L^1$ and $g$ is differentiable and $g' \in L^1$, then $(f*g)'=f*g'$ PROOF: For this proof I am asked to use the dominated convergence theorem It can be quickly arrived at that $$\begin{...
F.R.'s user avatar
  • 178
1 vote
0 answers
28 views

A Convolution Type Integral is Convergent in Limit

I am having trouble with solving the following problem: Let $\alpha \in (0, 1)$ and $T: [0, \infty) \to [0, \infty)$ be a continuous function with $\lim_{x \to \infty} x^\alpha T(x) = a_0 \in (0, \...
Partial T's user avatar
  • 593
1 vote
0 answers
44 views

$\|\chi_A*\chi_B\|_{\mathbb L^\infty}\leq \min\{\lambda(A),\lambda(B)\}$

Let $A,B \subseteq \mathbb R^d$ lebesgue measurable with finite Lebesgue measure and $f=\chi_A*\chi_B$ Show that $\|f\|_{L^\infty}\leq \min\{\lambda(A),\lambda(B)\}$ I know that $\|f\|_\infty\leq \...
marc's user avatar
  • 242
1 vote
1 answer
161 views

prove that $L^1$ is not unital under the convolution product

Prove that $L^1([-\pi, \pi))$ (the space of integrable $2\pi$ periodic functions using the norm $\lVert f\rVert_1 = \frac{1}{2\pi}\int_{-\pi}^\pi |f(x)|dx$) is not unital under the convolution product....
Fred Jefferson's user avatar
0 votes
2 answers
111 views

convolution of integrable functions

Prove that the convolution product $\star$ on $L^1 ([-\pi,\pi])$ ($2\pi$ periodic Lebesgue integrable functions on $\mathbb{R}$ with respect to the $L^1$ norm satisfies $f\star g(\theta) = \frac{1}{2\...
Fred Jefferson's user avatar

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