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7 votes
1 answer
711 views

What's the easiest way to prove the Riemann Zeta function has any zeros at all on the critical line?

I learned in my intro to complex analysis class that the Riemann Zeta has trivial zeros at the negative even integers; this follows from the Riemann Zeta Reflection identity and the behavior of the $\...
Faraz Masroor's user avatar
0 votes
1 answer
35 views

Termwise Differentiation of Convergent Series Involving the Riemann Zeta Function

Let $\zeta(s)$ be the Riemann zeta function. We know that $$\zeta(s) = \prod_p(1 - p^{-s})^{-1}, \ \operatorname{Re} s > 1$$ in the sense that the righthand side converges absolutely to $\zeta(s)$ ...
Johnny Apple's user avatar
  • 4,429
1 vote
1 answer
94 views

About the $n$th derivative of the Riemann zeta function on positive even integers

I know there exist a formula for the Riemann zeta function on positive even integers involving Bernoulli numbers. Do there exist any closed form for the $n$th derivative of the Riemann zeta function ...
Haidara's user avatar
  • 43
0 votes
0 answers
32 views

Stein Complex Analysis Proof of Chapter 6 Proposition 2.5

In Stein's Complex Analysis book, within the proof of Chapter 6 Proposition 2.5, the following claim is made: For $s = \sigma + it \in \mathbb{C}, n \geq 1$, then $$\left| \frac{1}{n^s} - \frac{1}{x^s}...
Mashe Burnedead's user avatar
1 vote
0 answers
95 views

Integral involving the zeta function along the critical line

WolframAlpha claims that $$\int\limits_{-\infty}^{\infty}\frac{|\zeta(\frac{1}{2}+it)|(3-\sqrt{8}\cos(\ln(2)t))}{t^2 +\frac{1}{4}}dt=\pi\ln(2)$$ and I don't know how to show this. I tried removing the ...
Darmani V's user avatar
  • 290
1 vote
1 answer
82 views

May I find $\zeta(-1)$ using the Hankel formula for $\zeta$, but not the reflection formula?

The Reimann zeta function for $\Re(s) > 1$ is $$\zeta(s) = \sum_{n=1}^{\infty} \frac{1}{n^s},$$ and we may show that the analytic continuation of $\zeta$ onto $\Re(s) \leq 1, s \neq 1$ is $$\zeta(s)...
Robin's user avatar
  • 3,940
0 votes
1 answer
82 views

Estimation of the absolute value of the $n$th non-real zero of the Riemann zeta function

Recently, I have been studying the oringinal proof of the prime number theory by Hadamard. I didn't get it on the estimation of the absolute value of the $n$th non-real zero of the $\zeta$ function by ...
Derek Xie's user avatar
0 votes
0 answers
71 views

the zero's of $f(s,a) = \sum_{n=1}^{a-1} n^{-s} $

I was looking at the zero's of $$f(s,a) = \sum_{n=1}^{a-1} n^{-s} $$ for integer $a>3$ in the strip $0 < \operatorname{Re}(s) < 1$. Now this clearly relates to the Riemann zeta: $$f(s,a) + \...
mick's user avatar
  • 16.4k
1 vote
0 answers
33 views

maximal continuation of $\Pi_2(x)$

Consider the functions for $k\in \Bbb N$ $$ \Pi_k(x) := \sum_{n \in \Bbb N} e^{\frac{\log^k n}{\log x}} $$ $\Pi_1(x)$ converges for real $1/e<x<1$. $\Pi_1(x)$ is a Riemann zeta function i.e. $\...
zeta space's user avatar
1 vote
1 answer
62 views

Proving that $\left|\sum_{n<x}\mu(n)\right|\ll x\exp(-c\sqrt{\log x})$ for some $c>0$

Assume that for $\sigma\ge 1-\frac{1}{(\log(2+|t|)^2}$ we have $$|\zeta(\sigma+it)|\gg\frac{1}{(\log(2+|t|))^2}.$$ Using Perron's formula and moving the line of integration to $\textrm{Re}(s)=1-\frac{...
turkey131's user avatar
  • 135
0 votes
1 answer
36 views

Proving $|\zeta(\sigma+it)|=O(\log t)$ uniformly for $1\le\sigma\le 2$ and $t\ge 10$

Prove that $|\zeta(\sigma+it)|=O(\log t)$ uniformly for $1\le\sigma\le 2$ and $t\ge 10$. The solution given by my lecturer is as follows. Recall the approximate formula for zeta, given by $$\zeta(s)=\...
turkey131's user avatar
  • 135
0 votes
0 answers
35 views

Estimates of the derivatives of $\Xi(s)$

The $\Xi$ Function is defined by $\Xi(s)=\xi(\frac{1}{2}+is)$, where $\xi(s)=\frac{1}{2}s(s-1)\pi^{-\frac{s}{2}}\Gamma(\frac{s}{2})\zeta(s)$. This is a problem from my homework: since we can write it ...
Fresh's user avatar
  • 81
1 vote
1 answer
91 views

The proof that the real zeta has the same domain as the complex valued zeta

I’m reading Havil’s book, Gamma. In Appendix E on p. 249 he has a proof that the complex valued zeta function has the same domain as the real valued zeta function. He basically shows that $\zeta(x) = \...
zeynel's user avatar
  • 437
4 votes
1 answer
105 views

How is $\zeta(0)$ actually $-1/2?$

I was searching around the forum, and I came across: $$\zeta(0) = \lim_{s\to 0}\, 2^{s-1} \pi^s \cdot \frac{\sin(\pi s/2)}{\pi s/2} \cdot \Gamma(1-s) \cdot s\zeta(1-s) = 2^{-1} \pi^0 \cdot 1 \cdot \...
SethRayCarlsen's user avatar
0 votes
1 answer
85 views

Understanding the proof of Theorem 10.2 in Montgomery & Vaughan's Multiplicative Number Theory

In Theorem 10.2 of the book of Montgomery & Vaughan's Multiplicative Number Theory there are two claims comes without any explanation: 1- For $0 < u < \infty$, $(u + a)^{s−1} ≪ |a|^{σ−1}$ ...
Ali's user avatar
  • 281

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