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1 vote
1 answer
82 views

Find the Laurent expansion of $f(z) = \sin{\frac{1}{z(z-1)}}$ in $0<|z-1|<1$

Here is my idea: $\sin{\frac{1}{z(z-1)}} = \sin{\left( \frac{-1}{z} + \frac{1}{z-1}\right)} = \sin{\left(\frac{1}{z-1} - \frac{1}{z}\right)} = \sin{\frac{1}{z-1}}\cos{\frac{1}{z}} - \cos{\frac{1}{z-1}}...
Irbin B.'s user avatar
  • 172
1 vote
1 answer
46 views

Taylor-Laurent series expansions

I'm having some issues finding how to series expand some complex functions that my professor gave past years in exams. For example, in this exercise, it is asked to find the first two terms of the ...
deomanu01's user avatar
  • 113
2 votes
0 answers
71 views

Entire function such that $f(\sin z)=\sin(f(z))$

Find all the entire functions $f$ such that $$f(\sin z)=\sin(f(z)),\quad z\in\mathbb C.\tag {*}$$ The motivation to ask this question is an old post Find all real polynomials $p(x)$ that satisfy $\...
Riemann's user avatar
  • 8,455
0 votes
1 answer
92 views

Taylor series expansion of $f(z)=\frac{\log(1+z^2)}{(1-z)\sinh z}$

I need to find the first 3 terms of the Taylor expansion around $z=0$ of the complex function: $$f(z)=\frac{\log(1+z^2)}{(1-z)\sinh z}$$ I tried the following way (obviously the radius of convergence ...
Leonardo's user avatar
  • 711
1 vote
0 answers
51 views

Series expansion of $z^{1/3}$ at z=1

Obtain the series expansion of $f(z)=z^{1/3}$ at z=1 such that $1^{1/3}=\frac{-1+i\sqrt{3}}{2}$ The way I've done it is the following: I need $1^{1/3}=e^\frac{i\arg{1}}{3}=e^{i2\pi/3}$, so any branch ...
Mateo's user avatar
  • 63
1 vote
0 answers
29 views

Find the Laurent series for the following function [duplicate]

Find the Laurent series for $f(z)=\frac{2z-3}{z^2-3z+2}$ centered in the origin and convergent in the point $z=\frac32$, specifying it's convergence domain. So I'm having troubles understanding what ...
Ulshy's user avatar
  • 57
0 votes
2 answers
73 views

Solving Power Series Equations if we introduce Logarithmic Terms

If we have a complex power series equation like $$ \sum_{n=0}^{\infty} a_n z^n = \sum_{n=0}^{\infty} b_n z^n $$ then we can conclude $a_n = b_n$. We can see this by viewing $z^n$ as basis elements, or ...
leob's user avatar
  • 351
0 votes
0 answers
47 views

Why this equation holds?

Can someone help me why does this equation holds: $\sum_{\rho}(1/2 + t -\rho)^{-s}= e^{i\pi s/2}\sum_{k=1}^{\infty}(\tau_k+it)^{-s}+e^{-i\pi s/2}\sum_{k=1}^{\infty}(\tau_k-it)^{-s}$ for $\rho=1/2 \pm ...
Bona's user avatar
  • 87
0 votes
1 answer
153 views

Is this the expansion for any known function?

The expansion is $$\sum_{n=1}^{\infty}\frac{x^n}{n!(n-1)!}\left[c(1+c)\dots((n-1)^2+c)\right]$$ So the first 3 terms are $cx$, $\dfrac{c(1+c)}{2}x^2$, $\dfrac{c(1+c)(4+c)}{12}x^3$.
mp62442's user avatar
  • 35
0 votes
1 answer
64 views

Finding the Maclaurin series for the given function.

I am dealing with a problem that says:Find the Maclaurin series for the function $f(x)=\ln(1+x+x^2)$. I have tried to write the expression inside the brackets exactly, $1+x+x^2$ as a product of two ...
ghost15's user avatar
0 votes
0 answers
41 views

When is it necessary to expand out the first term(s) of a power series?

I'm comfortable with the process of finding the Laurent series for a complex function, but in many of the answers from the textbook the first few terms will be expanded from it. Since I'm teaching ...
Jackson's user avatar
  • 381
1 vote
0 answers
70 views

Is there a "closed form" for the taylor series of $\sqrt{1+f[x]}$?

I would like a simple, computationally viable expansion in $x$ of $\sqrt{1+f[x]}$. If we taylor expand $f[x] $ itself inside the square root to first couple of orders, and expand the square root for ...
Noam's user avatar
  • 67
1 vote
1 answer
72 views

Expansion of an analytic function in the unit disk

I am trying to solve the following problem: Suppose that $f(z) = \sum_{k=0}^{\infty} c_kz^k$ is an analytic function in $\mathbb{D} = \{z\in\mathbb{C}:|z|<1\}$. Prove that $F(z)=\sum_{k=0}^{\infty}...
Lord Vader's user avatar
0 votes
1 answer
738 views

Power series expansion of 1/(1+z)^2 around z=1 [duplicate]

I'm struggling with getting the power series/Taylor series expansion of $f(z) = \frac{1}{(1+z)^2}$ around $z_0 = 1$. Usually, I would do a partial fraction decomposition, and then do some re-arranging ...
jReX's user avatar
  • 9
0 votes
1 answer
60 views

Radius of convergence of an infinite series by using a theorem.

Before I ask the question, I will explain a bit of theory and then give the question. Theorem 3: The derived series of a power series has the same radius of convergence as the original series. The ...
Oliver4's user avatar
  • 21

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