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0 votes
0 answers
52 views

Derivative of square root via power series

The power/Taylor series for the complex function $h(w)=\sqrt{w}$ is given by $$h(w) = \sum_{k=0}^\infty \frac{a_k}{k!}(w-1)^k$$ where $a_0 = 1, a_{k+1} = (\frac{1}{2}-k)a_k$. Now is my question: how ...
Osteo's user avatar
  • 89
0 votes
1 answer
46 views

Cauchy residue formula question

The Cauchy formula can be used to find the $n$th derivative of an analytical function $f(z)$ as $$ \frac{d^nf}{dz^n}\bigg|_{z=z_0}=\frac{n!}{2\pi i }\oint \frac{f(z)}{(z-z_0)^{n+1}}dz $$ which happens ...
AngusTheMan's user avatar
2 votes
4 answers
99 views

By differentiation or otherwise, prove that $(c(z))^2 +(s(z))^2 = 1$

Assume that the two power series $s(z) = \sum a_nz^n$ and $c(z) =\sum b_nz^n$ are convergent for all $z\in \mathbb{C},$ and that they satisfy the relations $s'(z) = c(z), c'(z) =-s(z).$ Deduce the ...
user avatar
0 votes
1 answer
26 views

Convergence of the derivative of a power series on the boundary

I'm wondering if the series $\sum a_nx^n$ converges at $x=R$, the radius of convergence, can we conclude that it's derivative also converges when x=R ?
Xixi's user avatar
  • 39
0 votes
2 answers
241 views

Complex analysis power series / derivative

I need some help with this exercise: Show that there is no such power series $f(z)=\sum_{n=0}^{\infty}C_nz^n$ such that: $f(z)=1$ for $z=\frac{1}{2}, \frac{1}{3}, \frac{1}{4},\ldots,$ $f'(0)>0$. ...
blue_green_yellow's user avatar
1 vote
2 answers
93 views

Uniform convergence of $\sum_{n=0} ^\infty \frac{(-1)^n}{2n+1} \left(\frac{2z}{1-z^2}\right)^{2n+1}$

I am given: $$ f(z)=\sum_{n=0} ^\infty \frac{(-1)^n}{2n+1} \left(\frac{2z}{1-z^2}\right)^{2n+1}$$ And asked to show that this complex function series converges uniformly for $|z|\leq \frac{1}{3}$. ...
user avatar
1 vote
3 answers
625 views

Prove if $k^\text{th}$ derivative of an entire function $f$ is polynomial, then $f$ itself is polynomial. Where's my mistake?

The exact wording of the question is as follows: Let $f$ be an entire function. Suppose there exists a positive integer $k$ such that $k^\text{th}$ derivative $f^{(k)}$ is a polynomial. Prove that $...
Atonal's user avatar
  • 133
1 vote
3 answers
71 views

Where can I find a quick proof that a function is analytic if and only if it admits a serie expansion?

I am currently studying functional analysis following the Aliprantis book. There, they define functions $f: O \longrightarrow X$ where $O$ is an open subset of $\mathbb{C}$ and $X$ is a Banach space. ...
user404720's user avatar
1 vote
0 answers
56 views

I'm looking to find a power series for a solution f where $zf''(z)+f(z)=0$

I'm looking to find a power series for a solution f where $zf''(z)+f(z)=0$ and $f(0)=0$ and $f'(0)=1$ and with the assumption $\sum_{k=1}^∞{a_k z^k}=0$ So far I have done this: $\sum_{k=1}^∞{k^2 ...
Tay's user avatar
  • 11
1 vote
1 answer
117 views

Derivative of exp with definition of differentiability

Prove with the definition of differentiability that $\exp(z)$ is differentiable in $\mathbb C$ and $(\exp(z))' = \exp(z)$ for all $z \in \mathbb C.$ I tried: \begin{align*} \frac{\exp(z+h) - \exp(z)}...
numerion's user avatar
  • 683
3 votes
1 answer
2k views

How to prove that a complex power series is differentiable

I am always using the following result but I do not know why it is true. So: How to prove the following statement: Suppose the complex power series $\sum_{n = 0}^\infty a_n(z-z_0)^n$ has radius of ...
numerion's user avatar
  • 683