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1 vote
0 answers
52 views

Proof that a homeomorphism map boundaries to boundaries

I want to prove that if I have two topological spaces $X$ and $Y$, with $A \subset X$, and a homeomorphism $f : X \to Y$, then $f(\partial A) = \partial \big(f(A)\big)$. I saw a proof here: https://...
MathLearner's user avatar
  • 1,021
1 vote
0 answers
44 views

Understanding continuity in $\hat{\mathbb{C}}$

Let $\hat{\mathbb{C}}$ denote the Riemann sphere. Let $f:B_1(0) \to \hat{\mathbb{C}}$ be continuous. If $f$ is continuous at $z$ and non-zero, then $1/f(z)$ is continuous at $z$ as well. My question ...
Ty Perkins's user avatar
0 votes
0 answers
36 views

Identity theorem for (real) analytic functions on lower dimensional subsets

For simplicity, we will deal with $\mathbb{R}^2$. Let's assume we have an one-dimensional submanifold $M_1 \subset \mathbb{R}^2$ and two analytic function $F,G: M_1 \rightarrow \mathbb{R}$. If I know $...
NicAG's user avatar
  • 661
0 votes
1 answer
332 views

definition of limits and continuity in complex analysis

Here is the definition my textbook gives: Suppose a have a function $f$ with domain $\{z \in \mathbb{C} : |z| \le 1\}$. The point $i$ has $|i|=1$ and is in $f$'s domain. $f$ is not defined on any ...
jenny9's user avatar
  • 77
0 votes
1 answer
113 views

Show that if $M ≥ 0$ and $|f(z)| ≤ M$ for all $z ∈ ∂V$ , then $|f(z)| ≤ M$ for all $z ∈ V $

Suppose that V is a bounded open subset of the plane and $f ∈ C(\overline V) ∩ H(V)$ i.e. $f$ is continuous on $\overline V$ and $f\restriction_V$ is holomorphic on $V.$ Show that if $M ≥ 0$ and $|f(z)...
reiki's user avatar
  • 61
6 votes
2 answers
2k views

No continuous injective functions from $\mathbb{R}^2$ to $\mathbb{R}$

Which of the following statements is true? $(a)$ There are at most countably many continuous maps from $\mathbb{R}^2$ to $\mathbb{R}$ $(b)$ There are at most finitely many continuous surjective maps ...
user-492177's user avatar
  • 2,589
-2 votes
1 answer
77 views

Continuous bijective mapping between $\mathbb{C}$ and $\mathbb{C}^*$

Is there a continuous bijective mapping from $\mathbb{C}$ to $\mathbb{C}^* = \mathbb{C}\setminus\{0\}$?
Joseph Seventy's user avatar
4 votes
1 answer
876 views

When does a bounded continuous function extend continuously to its closure

Let $\Omega$ be a domain in $\mathbb{C}^n$. Let $f:\Omega\longrightarrow\mathbb{C}$ be a bounded continuous function. I wanted know if there are any necessary and sufficient conditions for $f$ to be ...
user31459's user avatar
  • 386
0 votes
2 answers
304 views

Proving a function to be an open map

How can we prove that the function $f: S^1 \rightarrow S^1$ defined as $z \mapsto z^2$ is a continuous and open map using topological arguments? Here $S^1$ represents the unit circle in complex plane, ...
Singh_Gunjeet's user avatar
1 vote
2 answers
251 views

Closure and continuous map

Let $S_i$ be a countable family of sets and $f$ a continuous map (say everything is in the complex plane). Is it true that $$ f( \overline{ \cup_i S_i } ) = \overline{ \cup_i f( S_i ) } $$ or perhaps ...
Per Alexandersson's user avatar
2 votes
0 answers
443 views

Separate continuity and analyticity in one variable implies joint continuity?

A theorem of Hartog states that if $U \subseteq \mathbb C$ is open and $f : U \times U \to \mathbb C$ is analytic when we fix any variable ('separately analytic'), then it is continuous. In general, ...
Bart Michels's user avatar
  • 26.5k
0 votes
1 answer
82 views

How $f(z)=z^n$ is continuous but its inverse doesn't map an open set to an open set?

If a map $f: X \to Y$ is continuous then $f^{-1}(V)$ is open set in $X$ whenever $V$ is an open set in $Y$. Consider $f: \mathbb{C} \to \mathbb{C}$ by $f(z)=z^n$. By this map the sector $r≤a$, $0≤θ&...
user avatar
0 votes
2 answers
71 views

$\mathbb{C}$ similar to $\mathbb{R^2}$ for some properties

I have a doubt that I would like to clear, it concerns the similarities between $\mathbb{R^2}$ and $\mathbb{C}$. In particular, I am investigating the properties about the compactness of the domain ...
ofir_13's user avatar
  • 584
0 votes
3 answers
4k views

Does a continuous mapping have to map the boundary to the boundary

This question comes from when I read my Complex Analysis book. On the chapter of Mobius transformation, there is an example:"construct a Mobius transformation that maps $\{\mathrm{Im} (z)>0\}$ ...
Edward Wang's user avatar
  • 1,856

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