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0 votes
0 answers
40 views

Finding particular solution using domain transformation

$$ φ(n)=5 φ\left(\frac{n}{2}\right)-6 φ\left(\frac{n}{4}\right)+n $$ where $$ \varphi (1) = 2 \\ \text{and} \\ \varphi (2) = 1 $$ With $n=2^x$, I have the following equation. Am I wrong in this ...
Soner from The Ottoman Empire's user avatar
-1 votes
1 answer
39 views

Coefficient of an expansion

Find the coefficient of $x^k$ in $(x+a)(x+b)...(x+n)$ where $a$, $b$ and $n$ are integers. I am not able to approach this problem.
exilednick's user avatar
0 votes
1 answer
110 views

Symmetric Polynomials: Binomial identity

Consider the following equality of symmetric polynomials of degree $n$: $\sum\limits_{i=1}^{n-1}c_ix^iy^{n-i}+\sum\limits_{i=1}^{n-1}c_i(x+y)^iz^{n-i}=\sum\limits_{i=1}^{n-1}c_iy^iz^{n-i}+\sum\...
Jean Paul's user avatar
11 votes
3 answers
1k views

Smoothstep sigmoid-like function: Can anyone prove this relation?

The Smoothstep sigmoid-like function is defined as the polynomial $$ \begin{align} \operatorname{S}_N(x) &= x^{N+1} \sum_{n=0}^{N} \binom{N+n}{n} \binom{2N+1}{N-n} (-x)^{n} \qquad N \in \mathbb{Z}...
robert bristow-johnson's user avatar
11 votes
1 answer
202 views

Is the given binomial sum almost everywhere negative as $K\to\infty$?

The binomial sum is as follows: $$\mathcal {L}^K(\theta)= \sum_{i=\lceil{K/2}\rceil}^K \binom{K}{i}\theta^i\left((1-\theta)^{K-i}-\frac{1}{2}(1-\theta)^{-K}(1-2\theta)^{K-i}\right)$$ which can also ...
Seyhmus Güngören's user avatar