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1 vote
1 answer
87 views

Solve for $x$: $3^{2x}=5^{x-1}$

So I recently got myself an AP Precalculus book (for anyone who wants to know which book, I will have that in the "To Clarify" section at the bottom of this post) and was looking through ...
CrSb0001's user avatar
  • 2,652
3 votes
2 answers
194 views

How to solve for $x$ in $2^x+4^x=8^x$

So I was bored, and decided to do some math for fun. This was mostly to see if I could still do fairly complex math. After a while, I came up with this to see if I could still do some reasonably ...
CrSb0001's user avatar
  • 2,652
1 vote
2 answers
122 views

But will $(\tan(x))^{\ln(\sin(x))}$ ever equal $(\ln(\cot(x)))^{\cos(x)}$

So I was looking through the homepage of Youtube, looking for more math problems that I thought that I might be able to solve when I got bored, since either I had already solved them before, I had ...
CrSb0001's user avatar
  • 2,652
-1 votes
1 answer
176 views

How to solve $b^x$=$\log_bx$?

I was looking through YouTube when I came across this video by blackpenredpen. The question was$$\text{Solve: }b^x=\log_bx$$which I thought I might be able to solve. Here is my attempt at solving it:$$...
CrSb0001's user avatar
  • 2,652
2 votes
1 answer
142 views

How to solve $\ln(-2)=z$?

$$\color{white}{\require{cancel}{.}}$$So I was looking through the Youtube homepage looking for math equations that I might be able to solve and I found this video by blackpenredpen. The question was ...
CrSb0001's user avatar
  • 2,652
0 votes
1 answer
96 views

Solving for y in $\log_5(3y)+\log_5(9)=\log_5(405)$

$\color{white}{\require{cancel}{\text{placeholder}}}$ I have been doing some fairly simple math for fun lately to see what I can remember. Other than my other question that I had about another of my ...
CrSb0001's user avatar
  • 2,652
5 votes
3 answers
265 views

Solve for $x$ correct to $3$ decimal places: $27=\frac{1}{6^x}$

$\color{white}{\require{cancel}{placeholder}}$ So recently, I decided to do some fairly basic trigonometry for fun to see what I was able to remember. I decided to give myself a challenge and ...
CrSb0001's user avatar
  • 2,652
3 votes
2 answers
95 views

Solve $(x^2-5x+5)^{x^2+4x-60}=1$-Missing Solution

Problem: $$(x^2-5x+5)^{x^2+4x-60}=1$$ Attempt: Taking logs on both sides: $$(x^2+4x-60)\ln(x^2-5x+5)=0$$ Yields 4 solutions: $$[1]: x^2+4x-60=(x+10)(x-6)=0 \implies x=-10,6$$ $$[2]: x^2-5x+5=1 \...
AtKin's user avatar
  • 608
0 votes
1 answer
30 views

What is the maximum $b$ for which $\log_b(x) = \log_b(\log_b(x))$ has real solutions? And would there be 1 or 2 solutions?

$\log_b(x) = \log_b(\log_b(x))$ Based on preliminary observations on Desmos, $1.44<b<1.45$. For $b$ less than that, the identity has 2 real solutions, and for $b$ greater than that, it has 0 ...
Josh's user avatar
  • 467
2 votes
2 answers
648 views

What is wrong with my approach to solving $x^{\log25} + 25^{\log x} = 10\;$?

Found this equation on the web: $$x^{\log25} + 25^{\log x} = 10$$ The person solved by substitution and got $x = \sqrt{10}$ which satisfies the equation. I tried different ways after following the man'...
Frederick's user avatar
  • 119
0 votes
1 answer
41 views

Exponents and bases

I have some doubts in understanding the necessity of some steps in the following situation. While solving an algebraic problem, I came across an expression of the following type, where I have to solve ...
rks's user avatar
  • 127
1 vote
3 answers
60 views

Proving that $f(x) = 6\ln(x^{11}-4) -2$ is one-to-one

Please verify my proof, and if there are any mistakes please explain. Prove that that this function is one-to-one: $f(x) = 6\ln(x^{11}-4) -2$. Suppose $f(x_1) = f(x_2)$ $\implies 6\ln(x_1^{11}-4) -2 =...
Hayk Khachatryan's user avatar
2 votes
2 answers
106 views

$\log_2(8)= a$; $\log_2(5)= b$; $\log_2(7) = c$; express $\log_2\sqrt{21}$ in terms of $a, b, c$

Not sure where to start with this question. I could try \begin{align} & \frac12\log_2(21) \\[6pt] & \frac12\log_2(7 \cdot 3) \\[6pt] & \frac12\log_2(7) + \frac12\log_2(3) \\[6pt] & \...
Justin's user avatar
  • 31
3 votes
2 answers
48 views

Is there a gap in my proof? If $a>1$ and $\log_ab_1>\log_ab_2$, then $b_1>b_2.$

I need to prove that If $a>1$ and $\log_ab_1>\log_ab_2$, then $b_1>b_2.$ My attempts: Let $\log_ab_1=x, \log_ab_2=y$ we have $\begin{cases} a^x=b_1 \\ a^y=b_2 \end{cases} \Longrightarrow a^...
user avatar
0 votes
1 answer
36 views

Find number of solutions to the equation log

Find number of solutions to the equation $\log_{x+1}{(x-\frac{1}{2})}=\log_{x-\frac{1}{2} }{(x+1)}$ The only solutions in the complexes are 1, and 3/2? Let $(x+1)^a=(x-\frac{1}{2})$ and thus $(x-\...
Lambert macuse's user avatar

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