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2 votes
2 answers
133 views

Does the second positive solution (besides $x = 1$) of the equation $e^{x^2-1}=x^3-x\ln x$ have a closed form?

Does the equation $$e^{x^2-1}=x^3-x\ln x$$ have a closed form solution ? The given equation has $2$ positive real roots. Graphically It is not hard to see that $x=1$ is a rational solution. The ...
hardmath's user avatar
  • 644
4 votes
6 answers
465 views

How can we find Lambert W solution to $\dfrac {x\ln x}{\ln x+1}=\dfrac{e}{2}$?

Find all real solutions: $$\frac {x\ln x}{\ln x+1}=\frac{e}{2}$$ Cross multiplication gives $$2x\ln x=\ln (x^e)+e$$ I didn't see any useful thing here. I tried solving this equation in WA. The ...
hardmath's user avatar
  • 644
2 votes
4 answers
254 views

How to solve $x + 3^{x} = 4$ using Lambert W Function.

As stated in the title I am trying to solve the equation $$x + 3^{x} = 4$$ using Lambert W Function and which led me to the result $$x = 4 - \frac{W(3^{4} \ln{3})}{\ln{3}}$$ and driven by the belief ...
Michael Stevens's user avatar
-1 votes
1 answer
199 views

How to solve for $x$ from $x + \ln(x) = \ln(c)$?

How do I solve this equation for P? For everything I've tried, P ends up trapped in an exponent or another natural log. $$ \ln\left(\frac{GC}{a}\right) = hP + \ln(P) $$
Koryak21's user avatar
-1 votes
1 answer
79 views

All real and closed-form roots of $\log_2x=\frac {2^{x-1}}{x}$

What are the closed-form roots of $$\log_2x=\frac {2^{x-1}}{x}$$ ? My attempts: Closed-form means, I assume that the Lambert W function can work. I know that, at least $x>0$. Wolfram Alpha gives ...
User's user avatar
  • 1,659
5 votes
5 answers
228 views

Is there an algebraic solution to $\log_{\sqrt2}{\left(x\right)} = (\sqrt2)^x$?

I’m trying to solve $$\log_{\sqrt2}{\left(x\right)} = (\sqrt2)^x$$ My next step is $$\ln{x}= (\sqrt2)^x\ \cdot\ \ln\sqrt2$$ EDIT: I’m only up to high school math.
Nimna De Silva's user avatar
1 vote
0 answers
285 views

curve equation from $\frac{1}{2^x}-\frac{1}{3^x}=\frac{1}{2^y}-\frac{1}{3^y}$

Is there a way to find the equation of the curved part for this: $$\frac{1}{2^x}-\frac{1}{3^x}=\frac{1}{2^y}-\frac{1}{3^y}$$ for $x$? See WolframAlpha for the plot. The curve is crossing the line $y=x$...
user489810's user avatar
0 votes
1 answer
157 views

Solving Equation involving Lambert W function

I have the following equation that depends on the values $a, q, x$ where $a,q>2$ are positive non-zero real numbers. $$ y = \log(x\log(2) + a) - \left(2-\frac{1}{2^x}\right) q $$ Now I was able to ...
wjmccann's user avatar
  • 3,105
0 votes
1 answer
76 views

How to find $x$ for $-\frac{1}{\sqrt{2}x^{\frac{3}{2}}}=-\frac{1}{4}e^{-\frac{x}{4}}\left(A-B\right)$

The title pretty much explains it; I've had trouble with this because when taking the logarithm of both sides $x$ can never be isolated. I have been looking into the Lambert W function, but I've never ...
user avatar
2 votes
2 answers
196 views

What is the function $y = (1+1/x)^x$ solved for $x$?

I came across this function in algebra ($e$ being its limit as $x$ goes to infinity) while studying compounded interest. Since this function is a little modified from the real interest formula $y=(1+1/...
Abel Palmer's user avatar
1 vote
2 answers
127 views

How does one solve this kind of equation: $3^x=x+3$

How does one solve this kind of equation: $$3^x=x+3$$ I tried playing around with logs but it didn't get me anywhere. I plotted the two functions $f(x)=3^x$ and $g(x)=x+3$ on a graph to estimate the ...
Kantura's user avatar
  • 2,731
2 votes
0 answers
74 views

How can $x = \frac{b}{\ln(x + a)}$ be solved for $x$?

I've solved $x = \ln(x + a)$ by $x = -W(-e^{-a}) - a$, so I suspect that this will also involve the Lambert W function. However, I've been unable to make any progress due to the $x + a$, but without ...
Reed Oei's user avatar
  • 566
4 votes
2 answers
143 views

Is it possible to solve $k = \frac{x}{\ln(x)}$ for $x$?

Is it possible to solve $k = \frac{x}{\ln(x)}$ for $x$? My suspicion after a fruitless hour of manipulation is that it is not.
Bill Carey's user avatar