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I've seen this being used in a proof for limits and can't figure out why it is true.

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    $\begingroup$ $\ln (a^{b})=b\ln a$. $\endgroup$
    – Kavi Rama Murthy
    Commented Feb 2, 2022 at 12:17
  • $\begingroup$ @KaviRamaMurthy Thank you, that's it! $\endgroup$
    – Lost
    Commented Feb 2, 2022 at 12:17

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This just uses the logarithm law $\log(x^M) = M \log(x)$.

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