I'm having trouble of figuring out the steps to simplify the expression below, I have the answer but no clue how to reach this.
$$2^{(\log_4{x})} = \ \cdots \ = \sqrt[2]{x}$$
Update, thanks to the first comment I found the solution:
$2^{\log_{4}{x}} = \big( 4^{\log_{4}{x}} \big )^{1/2} = x^{1/2} = \sqrt{x}$
Thanks a lot! I wouldn't have figured it out otherwise.