HINT $\: $ First trivially inductively prove the Fundamental Theorem of Difference Calculus
$$\rm\ F(n)\ =\ \sum_{i\:=\:0}^n\ f(i)\ \ \iff\ \ \ F(n) - F(n-1)\ =\ f(n),\quad\ F(0) =\: f(0)$$
Yours is $\rm\ F(n)-F(n-1)\ =\ (n+1)! - n!\ =\ (n+1 -1)\ n!\ =\ n\ n!\ =\ f(n)\:,\:$ $\rm\ F(0) = 0 = f(0)\:.$
Note that by employing the Fundamental Theorem we have reduced the proof to the trivial verification of an equation. No ingenuity is required. In fact for hyperrational functions like factorials it is so trivial that there are algorithms that can mechanically verify such equalities.
Note that the proof of the Fundamental Theorem is much more obvious than that for your special case because the telescopic cancellation is obvious at this level of generality, whereas it is usually obfuscated in most specific instances. For further discussion see my many posts on telescopy.