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I have 3 questions which have to be answered through the application of the ring axioms. Let $R$ be a ring and show that:

a) $-0 = 0$. For this one you can assume that $(R,+)$ is a group and hence the identity is $0$, meaning $-0 + 0 = 0 + 0 = 0$. Is this correct?

b) $(-1)a = -a$ for all $a\in R$

c) $(-1)(-1) = 1$

(For b and c let $R$ be a ring with identity $1$).

I am not sure where to proceed for b) and c) and so any help to push me in the right direction would be greatly appreciated!

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  • $\begingroup$ Use distribution law on $(1+ (-1))a$ (additive inverse of $1$) and you get $a+(-1)a=0$ but you also know $a+(-a)=0$. $\endgroup$
    – orion
    Commented Nov 29, 2017 at 15:01

1 Answer 1

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For b), prove that $(-1)a+a=0$.

For c), use b).

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  • $\begingroup$ Got it! Thanks so much. $\endgroup$ Commented Nov 29, 2017 at 15:07

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