Although the question has already been answered pretty accurately, I would like to detail the typical reasoning used in this case.
What you want to prove is that $R \subset \{0 \} $.
What you should do, is try to prove that every element of $R$ is also an element of $\{0\}$.
As wrote User1006, the way to achieve this is:
Let $x\in R.$
$$\begin{align}x+0 &= x\cdot0 \\ x\cdot0 &= 0~~~~~\textrm{ by definition of ring}\end{align}$$ (This line is not that trivial)
$$\begin{align} ~~x+0 &= 0\\ x&= 0\,.\end{align}$$
$x$ is any element of $R.$
Hence, $\forall x \in R, x \in \{0\}.$
$$~~ R \subset \{0\}.$$
This is basically what User1006 wrote, but every time you come across such a question, this is the formality you should keep in mind.