So here's the puzzle. You're poisoned in the jungle and the only way to save yourself is to lick a special kind of frog. To make matters worse, only the female of that species will do. Licking the male frog doesn't do anything. The male and female frogs look identical. The only difference is that the male frog makes a sound and the female is silent.
So you run through the jungle and spot a frog in front of you. Before you could start running towards it you hear a sound behind you. You turn around and spot two frogs there. There's only time to run to one side.
Now, the best course of action is to run towards the two frogs and lick both. The reasoning is that there are 4 possible combinations of two frogs and knowing that one of them is male eliminates only one of those possibilities. Of the remaining three, two of them have at least one female frog. This gives you a $\frac 2 3$ chance of survival as opposed to a $\frac 1 2$ with the single frog.
Now here's my problem. The reason this works is because you don't know which frog made the sound. If you did, you'd have a $50\%$ chance with the other one. But wouldn't that imply that, if you for some reason turned around earlier to see which one made the sound, you would decrease your chances of survival? What's the explanation here?