This is in relation to the Euler Problem $13$ from http://www.ProjectEuler.net.
Work out the first ten digits of the sum of the following one-hundred $50$-digit numbers.
$37107287533902102798797998220837590246510135740250$
Now, this was my thinking:
I can freely discard the last fourty digits and leave the last ten.
$0135740250$
And then simply sum those. This would be large enough to be stored in a $64$-bit data-type and a lot easier to compute. However, my answer isn't being accepted, so I'm forced to question my logic.
However, I don't see a problem. The last fourty digits will never make a difference because they are at least a magnitude of $10$ larger than the preceding values and therefore never carry backwards into smaller areas. Is this not correct?