Timeline for Number of integer lattice points within a circle
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Sep 18, 2014 at 15:50 | history | edited | user2566092 | CC BY-SA 3.0 |
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| Sep 18, 2014 at 15:36 | history | edited | user2566092 | CC BY-SA 3.0 |
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| Sep 18, 2014 at 15:35 | comment | added | user2566092 | @Olayinka See the bottom of my updated answer for a possible fix. | |
| Sep 18, 2014 at 9:00 | comment | added | Olayinka | i understand, how do you suggest I fix this? | |
| Sep 17, 2014 at 22:35 | history | edited | user2566092 | CC BY-SA 3.0 |
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| Sep 17, 2014 at 22:31 | comment | added | user2566092 | @Olayinka Actually I did think of something. When your expression under the square root is a perfect square, it's possible because of round-off error that you will get a floating point number slightly less than the integer square root, so when you cast to an integer you will get 1 less than you should. Check to see if your incorrect answers are close but slightly smaller than the correct answer, and if so, that's likely what's going on. I'll update my answer to reflect this. | |
| Sep 17, 2014 at 22:29 | comment | added | user2566092 | @Olayinka I'm not sure what's going on then. If the formula is correct, your function should work for all integers $\leq 10^9$ if long longs are 64 bit, so the only thing I can think is that you are running on an older machine where long longs are still 32 bit. | |
| Sep 17, 2014 at 21:24 | comment | added | Olayinka | but the limit of r is $4\cdot 10^7$ which when squared can still fit into a signed long long | |
| Sep 17, 2014 at 21:11 | history | edited | user2566092 | CC BY-SA 3.0 |
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| Sep 17, 2014 at 21:05 | history | answered | user2566092 | CC BY-SA 3.0 |