Timeline for What's the behaviour of $I_n=\int_0^1\left(\frac1{\log x}+\frac1{1-x}\right)^ndx$, as $n \to \infty$?
Current License: CC BY-SA 3.0
23 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 13, 2017 at 12:20 | history | edited | CommunityBot |
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
|
|
| Oct 2, 2016 at 16:47 | history | edited | Olivier Oloa | CC BY-SA 3.0 |
deleted 162 characters in body; edited title
|
| Apr 10, 2016 at 5:46 | history | edited | Olivier Oloa | CC BY-SA 3.0 |
edited title
|
| Apr 8, 2016 at 6:51 | history | edited | Olivier Oloa | CC BY-SA 3.0 |
added 29 characters in body; edited tags
|
| Dec 26, 2014 at 3:04 | review | Close votes | |||
| Dec 26, 2014 at 4:21 | |||||
| Dec 20, 2014 at 18:55 | comment | added | Olivier Oloa | @Venus There is no duplicate, since in the question above, we were looking for an equivalent as $n$ tends to $+\infty$, which is very different from a closed-form, the latter doesn't give a simple equivalent of the integral. So you should remove the inappropriate term "duplicate" here. Thanks. | |
| Dec 20, 2014 at 14:23 | review | Close votes | |||
| Dec 20, 2014 at 15:19 | |||||
| Dec 20, 2014 at 14:06 | comment | added | Venus | possible duplicate of References to integrals of the form $\int_{0}^{1} \left( \frac{1}{\log x}+\frac{1}{1-x} \right)^{m} \, dx$ | |
| Jul 27, 2014 at 8:42 | comment | added | Olivier Oloa | @Nishant Please $A$ is the Glaisher-Kinkelin constant, I edited the question. Thanks. | |
| Jul 27, 2014 at 8:38 | history | edited | Olivier Oloa | CC BY-SA 3.0 |
Definition of $A$ the Glaisher-Kinkelin constant
|
| Jul 27, 2014 at 2:06 | comment | added | Nishant | What exactly is $A$? | |
| Jul 25, 2014 at 10:29 | vote | accept | Olivier Oloa | ||
| Jul 25, 2014 at 1:24 | answer | added | Antonio Vargas | timeline score: 26 | |
| Jul 24, 2014 at 9:31 | history | edited | Olivier Oloa | CC BY-SA 3.0 |
deleted 13 characters in body
|
| Jul 24, 2014 at 9:31 | comment | added | Mhenni Benghorbal | @OlivierOloa: Thanks for these links. | |
| Jul 24, 2014 at 9:26 | comment | added | Olivier Oloa | @Mhenni Benghorbal Please see the edit in the question. | |
| Jul 24, 2014 at 9:25 | history | edited | Olivier Oloa | CC BY-SA 3.0 |
added 1001 characters in body
|
| Jul 24, 2014 at 8:51 | comment | added | Mhenni Benghorbal | @OlivierOloa: Can you find a formula for this integral? | |
| Jul 24, 2014 at 8:15 | comment | added | Olivier Oloa | @Mhenni Benghorbal Yes: $$\frac 12 < \frac{1}{\log(1-x)} + \frac{1}{x} < 1, \quad 0<x<1.$$ Thanks. | |
| Jul 24, 2014 at 7:47 | comment | added | Mhenni Benghorbal | @OlivierOloa: It seems it approaches $0$. | |
| Jul 24, 2014 at 7:15 | comment | added | Mhenni Benghorbal | Are you interested in asymptotic behavior as n goes to infinity? | |
| Jul 24, 2014 at 3:34 | comment | added | Semiclassical | You've done a few others of this form. Can you link them in your question? | |
| Jul 24, 2014 at 3:21 | history | asked | Olivier Oloa | CC BY-SA 3.0 |