Timeline for Explain the Birthday Paradox
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 17, 2017 at 10:20 | comment | added | roottraveller | Can't explain better than this. Thanks man. | |
| Oct 3, 2016 at 10:07 | comment | added | Qqwy | Note that the link in this post is dead. | |
| Jun 18, 2014 at 13:37 | vote | accept | Nib | ||
| Jun 18, 2014 at 13:33 | comment | added | Nib | @ThomasAndrews, I was also confused and was thinking the same thing right now | |
| Jun 18, 2014 at 13:31 | comment | added | Thomas Andrews | @JoeyBF It is, but you need to know how to write the correct formula. For example, the formula you linked to was for 24 people... | |
| Jun 18, 2014 at 13:30 | history | edited | puru | CC BY-SA 3.0 |
added 96 characters in body
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| Jun 18, 2014 at 13:29 | comment | added | JoeyBF | @Nib Or also, WolframAlpha is your friend. | |
| Jun 18, 2014 at 13:29 | comment | added | puru | @ThomasAndrews It might overflow, however, if we go by my method, it's better to write a code and calculate! | |
| Jun 18, 2014 at 13:28 | comment | added | Thomas Andrews | @Nib I'd just use a calculator/computer to show that. | |
| Jun 18, 2014 at 13:27 | comment | added | puru | It's basically $(365)!/(353!)$*$1/(365)^{23}$ | |
| Jun 18, 2014 at 13:25 | comment | added | Nib | Allright, @puru, but how do you know that the series 1.(364/365).(363/365)....(343/365) is approximately 50% ??? | |
| Jun 18, 2014 at 13:24 | history | answered | puru | CC BY-SA 3.0 |