Skip to main content
Replaced equation and "big list" (different ways) question in title. It should not have been removed since that changed the question and reduced clarity
Link
Jam
  • 10.5k
  • 3
  • 29
  • 43

The Different ways to prove $\sum_{k=1}^\infty \frac{1}{k^2}=\frac{\pi^2}{6}$ (the Basel problem)

Remove unused links
Source Link
Parcly Taxel
  • 104.1k
  • 20
  • 113
  • 199

Different methods to compute $\sum\limits_{k=1}^\infty \frac{1}{k^2}$ (Basel The Basel problem)

As I have heard people did not trust Euler when he first discovered the formula (solution of the Basel problem) $$\zeta(2)=\sum_{k=1}^\infty \frac{1}{k^2}=\frac{\pi^2}{6}.$$$$\zeta(2)=\sum_{k=1}^\infty \frac{1}{k^2}=\frac{\pi^2}{6}$$ However, Euler was Euler and he gave other proofs.

I believe many of you know some nice proofs of this, can you please share it with us?

Different methods to compute $\sum\limits_{k=1}^\infty \frac{1}{k^2}$ (Basel problem)

As I have heard people did not trust Euler when he first discovered the formula (solution of the Basel problem) $$\zeta(2)=\sum_{k=1}^\infty \frac{1}{k^2}=\frac{\pi^2}{6}.$$ However, Euler was Euler and he gave other proofs.

I believe many of you know some nice proofs of this, can you please share it with us?

The Basel problem

As I have heard people did not trust Euler when he first discovered the formula (solution of the Basel problem) $$\zeta(2)=\sum_{k=1}^\infty \frac{1}{k^2}=\frac{\pi^2}{6}$$ However, Euler was Euler and he gave other proofs.

I believe many of you know some nice proofs of this, can you please share it with us?

Question Protected by Bumblebee
edited tags
Link
Bill Dubuque
  • 274.7k
  • 40
  • 308
  • 961
Notice removed Reward existing answer by Mr Pie
Bounty Ended with Pedro's answer chosen by Mr Pie
Notice added Reward existing answer by Mr Pie
Bounty Started worth 100 reputation by Mr Pie
Title improved for searchability
Link
Jack D'Aurizio
  • 355.4k
  • 41
  • 385
  • 834
Loading
k is the usual index for summation, n is used for the upper limit of summation.
Source Link
jimjim
  • 9.7k
  • 6
  • 41
  • 88
Loading
Added the (number-theory) tag
Link
Américo Tavares
  • 38.8k
  • 13
  • 108
  • 246
Loading
obsolete part removed
Source Link
VividD
  • 16k
  • 10
  • 63
  • 116
Loading
Added Wikipedia link
Source Link
Loading
edited inappropriate tags
Link
Loading
Notice removed Authoritative reference needed by CommunityBot
Bounty Ended with Markus Scheuer's answer chosen by CommunityBot
Notice added Authoritative reference needed by user187581
Bounty Started worth 50 reputation by CommunityBot
added 8 characters in body
Source Link
Loading
deleted 1 characters in body; edited title
Source Link
Loading
Tweeted twitter.com/#!/StackMath/status/102509731473670144
Post Made Community Wiki by Willie Wong
added 421 characters in body; edited tags
Source Link
Aryabhata
  • 82.6k
  • 10
  • 189
  • 276
Loading
edited tags
Link
Loading
edited tags
Link
Loading