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Oct 19, 2016 at 20:12 comment added tuskiomi The ending digit (in the 'ones' place) could be 1 as well, so long as the other digit was a 5.
Sep 4, 2013 at 16:31 review Suggested edits
Sep 4, 2013 at 16:33
Sep 20, 2011 at 17:27 comment added JSchlather @JDH I've added both.
Sep 20, 2011 at 17:24 history edited JSchlather CC BY-SA 3.0
Edit: Added scripts
S Sep 20, 2011 at 14:56 history suggested CommunityBot CC BY-SA 3.0
numbers as list
Sep 20, 2011 at 14:55 review Suggested edits
S Sep 20, 2011 at 14:56
Sep 20, 2011 at 14:48 comment added JDH Would it be possible for you to post your scripts?
Sep 20, 2011 at 6:47 history edited JSchlather CC BY-SA 3.0
Made some revision in light of a few errors.
Sep 20, 2011 at 6:36 comment added JSchlather @Dr jimbob You're right somewhere around writing the first program that condition slipped my mind and I was just looking at digits summing to ten. I'll revise my program and take some new data.
Sep 20, 2011 at 5:40 comment added dr jimbob Aren't all your answers above (in the edit numbers like 100000030000000000000030000000000000000000000003), having the 3 in the "ones" places not the "tens" place as required in the teacher's problem? I agree with the arguments that they appear to be many (and likely infinite per Michael's argument)? Shouldn't you just check for numbers in the forms $10^n + 3*10^m + 33$ or $3*10^n + 3*10^m + 31$ or $10^n+5*10^m+31$ or $6*10^n + 31$, $4*10^n + 33$, etc.
Sep 20, 2011 at 4:31 history edited JSchlather CC BY-SA 3.0
added new data
Sep 20, 2011 at 4:06 comment added JDH Thanks very much! ...and I am sure that Horatio will be interested to report these additional cases to his teacher! :-)
Sep 20, 2011 at 4:03 history answered JSchlather CC BY-SA 3.0