Timeline for Show that $\frac{a+b}{2} \ge \sqrt{ab}$ for $0 \lt a \le b$
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Jan 12, 2017 at 6:24 | answer | added | Atul Mishra | timeline score: 2 | |
| Jan 12, 2017 at 6:22 | answer | added | 郑豆浆 | timeline score: 1 | |
| Jan 12, 2017 at 6:16 | comment | added | Martin Sleziak | You can find some proofs also in this question and other posts linked there. | |
| Jan 12, 2017 at 6:14 | history | edited | Martin Sleziak |
edited tags
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| Nov 10, 2013 at 22:08 | history | edited | Jeel Shah | CC BY-SA 3.0 |
added 11 characters in body
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| Nov 9, 2013 at 14:32 | vote | accept | Jeel Shah | ||
| Nov 9, 2013 at 7:30 | answer | added | GTX OC | timeline score: 1 | |
| Nov 9, 2013 at 5:23 | comment | added | yoyo | $x^2\geq0 \ \forall x\in\mathbb{R}$ so voila, youre done | |
| Nov 9, 2013 at 5:22 | comment | added | imranfat | If you take the squareroot you are left with the absolute value of $a-b$ and that is still greater or equal to zero | |
| Nov 9, 2013 at 5:21 | answer | added | Cameron Buie | timeline score: 4 | |
| Nov 9, 2013 at 5:21 | comment | added | lab bhattacharjee | artofproblemsolving.com/Wiki/index.php/Proofs_of_AM-GM | |
| Nov 9, 2013 at 5:20 | history | asked | Jeel Shah | CC BY-SA 3.0 |