Timeline for Calculating the Birthday Problem The Other Way Around
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 9, 2013 at 18:44 | vote | accept | Daniel Scocco | ||
| Oct 9, 2013 at 18:44 | comment | added | Daniel Scocco | You are correct. I formulated another way of explaining it below, but it was based on your idea. I'll select yours as the right answer. Could you take a look at my answer below and confirm it's the same thing (i.e., correct too)? | |
| Oct 9, 2013 at 18:37 | history | edited | Thomas Andrews | CC BY-SA 3.0 |
added 210 characters in body
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| Oct 9, 2013 at 18:15 | comment | added | Daniel Scocco | Thanks for that, but it's still not that clear for me. Are you saying it's too complex to calculate the probability the way I want? If not, how do you use your formula to get to the 0.5073 number? | |
| Oct 9, 2013 at 18:14 | history | edited | Thomas Andrews | CC BY-SA 3.0 |
added 152 characters in body
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| Oct 9, 2013 at 18:13 | comment | added | Thomas Andrews | Party time - that's my 1000th answer. :) | |
| Oct 9, 2013 at 18:06 | history | answered | Thomas Andrews | CC BY-SA 3.0 |