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Jun 15 at 19:11 answer added Vincenzo Tibullo timeline score: 0
May 23, 2019 at 6:09 answer added kees canal fp timeline score: 9
Oct 27, 2013 at 17:26 history edited Cameron Buie CC BY-SA 3.0
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Oct 27, 2013 at 17:17 audit First posts
Oct 27, 2013 at 17:17
Oct 14, 2013 at 9:21 history tweeted twitter.com/#!/StackMath/status/389682358385127424
Oct 10, 2013 at 19:59 audit First posts
Oct 10, 2013 at 21:34
Oct 8, 2013 at 9:10 audit First posts
Oct 8, 2013 at 9:10
Oct 7, 2013 at 21:12 history edited Stefan4024 CC BY-SA 3.0
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Oct 7, 2013 at 14:32 comment added Anonymous Pi Maybe this can get you started: wolframalpha.com/input/?i=x%5Ey%3Ey%5Ex or: wolframalpha.com/input/?i=x%5Ey%3Dy%5Ex
Oct 7, 2013 at 12:14 comment added Christian Fries @MårtenW: His problem is more specific. The link you posted is about x^a < y^b. He is considers the special case a=y, b=x
Oct 7, 2013 at 11:26 vote accept learner
Oct 7, 2013 at 11:18 comment added learner @MårtenW, no that's not it :) It's not on the internet actually.
Oct 7, 2013 at 10:56 answer added Henry timeline score: 114
Oct 7, 2013 at 10:50 comment added Mårten W Are you doing http://projecteuler.net/problem=99?
Oct 7, 2013 at 10:47 comment added lhf Not too large then. My answer probably works fine.
Oct 7, 2013 at 10:47 comment added learner @lhf, can be as large as 10^9.
Oct 7, 2013 at 10:46 comment added lhf How large are the numbers?
Oct 7, 2013 at 10:44 history edited learner CC BY-SA 3.0
typo
Oct 7, 2013 at 10:44 comment added learner @lhf, Fast and in checking among n such pairs of numbers, n/10 could go wrong. Could you please help me deduce what accuracy I'm looking for?
Oct 7, 2013 at 10:40 comment added lhf You want fast or robustly correct?
Oct 7, 2013 at 10:39 comment added pitchounet You can test if $\ln(y) + \ln \big( \ln(x) \big) > \ln(x) + \ln \big( \ln(y) \big)$.
Oct 7, 2013 at 10:38 answer added lhf timeline score: 26
Oct 7, 2013 at 10:35 history asked learner CC BY-SA 3.0